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		<title>The isoperimetric inequality via mass transport</title>
		<link>https://partialdifferentialequations.wordpress.com/2011/04/04/the-isoperimetric-inequality-via-mass-transport/</link>
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		<pubDate>Mon, 04 Apr 2011 06:00:40 +0000</pubDate>
		<dc:creator>Nestor</dc:creator>
				<category><![CDATA[Mass transport]]></category>
		<category><![CDATA[Isoperimetric inequality]]></category>
		<category><![CDATA[mass transport]]></category>

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		<description><![CDATA[Last week at MSRI we started a  Brown Bag seminar informally named &#8220;Beautiful computations&#8217; Seminar&#8221;  (credit goes to Juan Luis Vazquez for the idea). The purpose of the seminar (which will be taking place on thursdays around lunch time) is having very short talks explaining a specific &#8220;trick&#8221; or idea that the speaker considers both [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=631&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Last week at MSRI we started a  Brown Bag seminar informally named &#8220;Beautiful computations&#8217; Seminar&#8221;  (credit goes to <a href="http://www.uam.es/personal_pdi/ciencias/jvazquez/">Juan Luis Vazque</a>z for the idea). The purpose of the seminar (which will be taking place on thursdays around lunch time) is having very short talks explaining a specific &#8220;trick&#8221; or idea that the speaker considers both beautiful and powerful.</p>
<p>For the first talk of this seminar I presented the proof of the Isoperimetric inequality using mass transport. The proof in this specific form was found independently by <a href="http://archive.numdam.org/ARCHIVE/AIHPC/AIHPC_1994__11_4/AIHPC_1994__11_4_411_0/AIHPC_1994__11_4_411_0.pdf">N. Trudinge</a>r and <a href="http://www.math.toronto.edu/mccann/papers/advances.pdf">R. McCann</a>, and it is certainly strongly influenced by work of M. Gromov which I am currently not competent to describe. Modulo the use of the Brenier-McCann theorem from Optimal transport, this is the shortest proof of the isoperimetric theorem  (in general dimensions) that I am aware of .</p>
<p>Further, this method of proof has rather deep ramifications, exemplified by  (sharp) quantitative refinements of the isoperimetric inequality for general non-isotropic area functionals, cf. <a href="http://cvgmt.sns.it/papers/figmagpra/">work of A. Figalli, F. Maggi and A. Pratelli</a>.</p>
<p><span id="more-631"></span></p>
<p>The <strong>Isoperimetric inequality</strong> says that given a domain  <img src='https://s-ssl.wordpress.com/latex.php?latex=%5COmega+%5Csubset+%5Cmathbb%7BR%7D%5En&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;Omega &#92;subset &#92;mathbb{R}^n' title='&#92;Omega &#92;subset &#92;mathbb{R}^n' class='latex' /> with a rectifiable boundary,</p>
<p style="text-align:center;"><img src='https://s-ssl.wordpress.com/latex.php?latex=c_n%5Cmbox%7BVol%7D%28%5COmega%29%5E%7B%5Cfrac%7Bn-1%7D%7Bn%7D%7D+%5Cleq+H_%7Bn-1%7D+%28%5COmega%29&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='c_n&#92;mbox{Vol}(&#92;Omega)^{&#92;frac{n-1}{n}} &#92;leq H_{n-1} (&#92;Omega)' title='c_n&#92;mbox{Vol}(&#92;Omega)^{&#92;frac{n-1}{n}} &#92;leq H_{n-1} (&#92;Omega)' class='latex' /></p>
<p style="text-align:left;"><img src='https://s-ssl.wordpress.com/latex.php?latex=c_n&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='c_n' title='c_n' class='latex' /> is a dimensional constant such that equality holds if and only if <img src='https://s-ssl.wordpress.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> is a ball.</p>
<p style="text-align:left;"><em>Proof.</em> Let <img src='https://s-ssl.wordpress.com/latex.php?latex=r%3E0&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='r&gt;0' title='r&gt;0' class='latex' /> be such that <img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cmbox%7BVol%7D%28B_r%29%3D%5Cmbox%7BVol%7D%28%5COmega%29&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;mbox{Vol}(B_r)=&#92;mbox{Vol}(&#92;Omega)' title='&#92;mbox{Vol}(B_r)=&#92;mbox{Vol}(&#92;Omega)' class='latex' />, then by the Brenier-McCann theorem (cf. <a href="http://books.google.com/books?id=q6kyE2ZkxrcC&amp;printsec=frontcover&amp;dq=topics+in+optimal+transportation&amp;source=bl&amp;ots=bSenV_Aaf_&amp;sig=f5WcHR1__TOkESn5RIqiG8dxtu8&amp;hl=en&amp;ei=UV2ZTczlDuPXiAK9gsXvCA&amp;sa=X&amp;oi=book_result&amp;ct=result&amp;resnum=3&amp;ved=0CDgQ6AEwAg#v=onepage&amp;q&amp;f=false">Villani&#8217;s book</a>) we know there is a continuous convex function <img src='https://s-ssl.wordpress.com/latex.php?latex=u%3A+%5COmega+%5Cto+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='u: &#92;Omega &#92;to &#92;mathbb{R}' title='u: &#92;Omega &#92;to &#92;mathbb{R}' class='latex' /> such that <img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cnabla+u&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;nabla u' title='&#92;nabla u' class='latex' /> is a measure preserving map from <img src='https://s-ssl.wordpress.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> to <img src='https://s-ssl.wordpress.com/latex.php?latex=B_r&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='B_r' title='B_r' class='latex' />, we thus have</p>
<p style="text-align:center;"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cmbox%7BVol%7D%28%5COmega%29%3D%5Cint_%7B%5COmega%7D1+dx+%3D%5Cint_%7B%5COmega%7D+%5Cmbox%7Bdet%7D%28D%5E2u%29%28x%29dx&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;mbox{Vol}(&#92;Omega)=&#92;int_{&#92;Omega}1 dx =&#92;int_{&#92;Omega} &#92;mbox{det}(D^2u)(x)dx' title='&#92;mbox{Vol}(&#92;Omega)=&#92;int_{&#92;Omega}1 dx =&#92;int_{&#92;Omega} &#92;mbox{det}(D^2u)(x)dx' class='latex' /></p>
<p style="text-align:left;">now, since <img src='https://s-ssl.wordpress.com/latex.php?latex=D%5E2u%28x%29+%5Cgeq+0&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='D^2u(x) &#92;geq 0' title='D^2u(x) &#92;geq 0' class='latex' /> for all <img src='https://s-ssl.wordpress.com/latex.php?latex=x+%5Cin+%5COmega&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='x &#92;in &#92;Omega' title='x &#92;in &#92;Omega' class='latex' /> we can apply the arithmetic-geometric  mean inequality to conclude that <img src='https://s-ssl.wordpress.com/latex.php?latex=n+%5Cleq+%5CDelta+u&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='n &#92;leq &#92;Delta u' title='n &#92;leq &#92;Delta u' class='latex' /> in <img src='https://s-ssl.wordpress.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> .  Integrating this relation and using the inequality above we arrive at</p>
<p style="text-align:center;"><img src='https://s-ssl.wordpress.com/latex.php?latex=n+%5Cmbox%7BVol%7D%28%5COmega%29+%5Cleq+%5Cint_%7B%5COmega%7D+%5CDelta+u%28x%29dx&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='n &#92;mbox{Vol}(&#92;Omega) &#92;leq &#92;int_{&#92;Omega} &#92;Delta u(x)dx' title='n &#92;mbox{Vol}(&#92;Omega) &#92;leq &#92;int_{&#92;Omega} &#92;Delta u(x)dx' class='latex' /></p>
<p style="text-align:left;">and by the divergence theorem this is the same as</p>
<p style="text-align:center;"><img src='https://s-ssl.wordpress.com/latex.php?latex=n%5Cmbox%7BVol%7D%28%5COmega%29+%5Cleq+%5Cint_%7B%5Cpartial+%5COmega%7Du_n+d%5Csigma&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='n&#92;mbox{Vol}(&#92;Omega) &#92;leq &#92;int_{&#92;partial &#92;Omega}u_n d&#92;sigma' title='n&#92;mbox{Vol}(&#92;Omega) &#92;leq &#92;int_{&#92;partial &#92;Omega}u_n d&#92;sigma' class='latex' /></p>
<p style="text-align:left;">since <img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cnabla+u&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;nabla u' title='&#92;nabla u' class='latex' /> <em>maps</em> <img src='https://s-ssl.wordpress.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> into <img src='https://s-ssl.wordpress.com/latex.php?latex=B_r&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='B_r' title='B_r' class='latex' /> we know that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Cu_n+%7C%5Cleq+%7C%5Cnabla+u%7C%5Cleq+r&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='|u_n |&#92;leq |&#92;nabla u|&#92;leq r' title='|u_n |&#92;leq |&#92;nabla u|&#92;leq r' class='latex' />, then</p>
<p style="text-align:center;"><img src='https://s-ssl.wordpress.com/latex.php?latex=n%5Cmbox%7BVol%7D%28%5COmega%29+%5Cleq+r%5Cint_%7B%5Cpartial+%5COmega%7Dd%5Csigma&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='n&#92;mbox{Vol}(&#92;Omega) &#92;leq r&#92;int_{&#92;partial &#92;Omega}d&#92;sigma' title='n&#92;mbox{Vol}(&#92;Omega) &#92;leq r&#92;int_{&#92;partial &#92;Omega}d&#92;sigma' class='latex' /></p>
<p style="text-align:center;"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Crightarrow+%5Cfrac%7Bn%7D%7Br%7D%5Cmbox%7BVol%7D%28%5COmega%29+%5Cleq+H_%7Bn-1%7D%28%5Cpartial+%5COmega%29&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;rightarrow &#92;frac{n}{r}&#92;mbox{Vol}(&#92;Omega) &#92;leq H_{n-1}(&#92;partial &#92;Omega)' title='&#92;rightarrow &#92;frac{n}{r}&#92;mbox{Vol}(&#92;Omega) &#92;leq H_{n-1}(&#92;partial &#92;Omega)' class='latex' /></p>
<p style="text-align:left;">Finally, we take into account that  <img src='https://s-ssl.wordpress.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='r' title='r' class='latex' />  was chosen so that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7CB_1%7Cr%5En%3D%5Cmbox%7BVol%7D%28%5COmega%29&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='|B_1|r^n=&#92;mbox{Vol}(&#92;Omega)' title='|B_1|r^n=&#92;mbox{Vol}(&#92;Omega)' class='latex' />, thus the last inequality is the same as</p>
<p style="text-align:center;"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cfrac%7Bn%7D%7B%7CB_1%7C%5E%5Cfrac%7B1%7D%7Bn%7D%7D%5Cleft+%28%5Cmbox%7BVol%7D%28%5COmega%29+%5Cright%29%5E%5Cfrac%7Bn-1%7D%7Bn%7D+%5Cleq+H_%7Bn-1%7D%28%5Cpartial+%5COmega%29+&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;frac{n}{|B_1|^&#92;frac{1}{n}}&#92;left (&#92;mbox{Vol}(&#92;Omega) &#92;right)^&#92;frac{n-1}{n} &#92;leq H_{n-1}(&#92;partial &#92;Omega) ' title='&#92;frac{n}{|B_1|^&#92;frac{1}{n}}&#92;left (&#92;mbox{Vol}(&#92;Omega) &#92;right)^&#92;frac{n-1}{n} &#92;leq H_{n-1}(&#92;partial &#92;Omega) ' class='latex' /></p>
<p style="text-align:left;">note that the constant is such that we have equality if <img src='https://s-ssl.wordpress.com/latex.php?latex=%5COmega+%3D+B_r&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;Omega = B_r' title='&#92;Omega = B_r' class='latex' />.</p>
<p style="text-align:left;">Conversely, if we have equality then in particular we must have equality in the arithmetic-geometric mean inequality, implying all eigenvalues of <img src='https://s-ssl.wordpress.com/latex.php?latex=D%5E2u&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='D^2u' title='D^2u' class='latex' /> must be the same, and so must all equal <img src='https://s-ssl.wordpress.com/latex.php?latex=1&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='1' title='1' class='latex' />. We conclude <img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cnabla+u&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;nabla u' title='&#92;nabla u' class='latex' /> is just a translation and thus <img src='https://s-ssl.wordpress.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> itself is a translation of <img src='https://s-ssl.wordpress.com/latex.php?latex=B_r&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='B_r' title='B_r' class='latex' /> and that finishes the proof.</p>
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		<title>MSRI Workshop Day 2 (a week later!): Free boundary problems involving thin films</title>
		<link>https://partialdifferentialequations.wordpress.com/2011/03/15/msri-workshop-day-2-a-week-later-free-boundary-problems-involving-thin-films/</link>
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		<pubDate>Tue, 15 Mar 2011 17:51:35 +0000</pubDate>
		<dc:creator>Nestor</dc:creator>
				<category><![CDATA[Fluid mechanics]]></category>
		<category><![CDATA[fluid mechanics]]></category>
		<category><![CDATA[gradient flow]]></category>
		<category><![CDATA[thin films]]></category>
		<category><![CDATA[Young-Laplace Law]]></category>

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		<description><![CDATA[As much as I would have liked to post something everyday of the conference, writing math blog posts still take me some time. The conference was terrific and as its usual whenever people were not at talks they were by some blackboard or some table finishing or starting a paper. Although its over, I took [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=677&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>
As much as I would have liked to post something everyday of the conference, writing math blog posts still take me some time. The conference was terrific and as its usual whenever people were not at talks they were by some blackboard or some table finishing or starting a paper. Although its over, I took plenty of notes from several of the talks and will go through some of them within the next week or so. Today I will give an overview of the talk given by <a class="snap_noshots" href="http://www-users.math.umd.edu/~mellet/">Antoine Mellet</a> (University of Maryland) on the second day of the workshop.</p>
<p>
Antoine&#8217;s talk discussed the thin film equation, I know very little about this subject (in fact all I know I learned from Antoine&#8217;s talk last week) so take some of the things I say with a grain of salt. The thin film equation models the spreading of a drop or thin layer of liquid on top of a flat, impermeable surface and there is a vast literature on the subject, see for instance <a class="snap_noshots" href="http://www.ams.org/notices/199806/bertozzi.pdf">this survey by Andrea Bertozzi</a>. Incidentally, Terry Tao discussed the closely related <a class="snap_noshots" href="http://en.wikipedia.org/wiki/Shallow_water_equations">shallow water wave equation</a> in a <a class="snap_noshots" href="http://terrytao.wordpress.com/2011/03/13/the-shallow-water-wave-equation-and-tsunami-propagation/">blog plost</a> yesterday.</p>
<p>
The <b>thin film equation</b> is the fourth-order non-linear equation
<p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u_t%2B%5Cmbox%7Bdiv%7D%28f%28u%29%5Cnabla+%5CDelta+u%29%3D0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u_t+&#92;mbox{div}(f(u)&#92;nabla &#92;Delta u)=0' title='&#92;displaystyle u_t+&#92;mbox{div}(f(u)&#92;nabla &#92;Delta u)=0' class='latex' /></p>
<p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u%3A+%5Cmathbb%7BR%7D%5Ed+%5Ctimes+%280%2CT%29+%5Crightarrow+%5Cmathbb%7BR%7D+&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;displaystyle u: &#92;mathbb{R}^d &#92;times (0,T) &#92;rightarrow &#92;mathbb{R} ' title='&#92;displaystyle u: &#92;mathbb{R}^d &#92;times (0,T) &#92;rightarrow &#92;mathbb{R} ' class='latex' /></p>
<p> where typically <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28u%29%3Du%5En%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(u)=u^n}' title='{f(u)=u^n}' class='latex' /> and one has boundary conditions (which I will explain in a bit) </p>
<p><span id="more-677"></span></p>
<p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cbegin%7Barray%7D%7Brlr%7D+u%7C_%7Bt%3D0%7D+%26+%3Du_0+%26+%5Cmbox%7B+initial+data+%7D+%5C%5C+%5Cnabla+u+%5Ccdot+%5Cnu%26+%3D+%5Ctheta+%5C%3B%5C%3B%5Cmbox%7B+on+%7D+%5Cpartial+%5C%7B+u%3E0%5C%7D+%26+%5Ctheta%5Cin%5Cmathbb%7BR%7D+%5Cmbox%7B+%09%28contact+angle+condition%29%7D%09%5C%5C+f%28u%29u%5E%7B-1%7D%5C%3B%5Cnabla+%5CDelta+u+%5Ccdot+%5Cnu+%26+%3D0%5C%3B%5C%3B%5Cmbox%7B+on+%7D+%5Cpartial+%5C%7B+u%3E0%5C%7D+%26+%5Cmbox%7B+no+flux+through+the+boundary%7D+%5Cend%7Barray%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;begin{array}{rlr} u|_{t=0} &amp; =u_0 &amp; &#92;mbox{ initial data } &#92;&#92; &#92;nabla u &#92;cdot &#92;nu&amp; = &#92;theta &#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} &amp; &#92;theta&#92;in&#92;mathbb{R} &#92;mbox{ 	(contact angle condition)}	&#92;&#92; f(u)u^{-1}&#92;;&#92;nabla &#92;Delta u &#92;cdot &#92;nu &amp; =0&#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} &amp; &#92;mbox{ no flux through the boundary} &#92;end{array}' title='&#92;displaystyle &#92;begin{array}{rlr} u|_{t=0} &amp; =u_0 &amp; &#92;mbox{ initial data } &#92;&#92; &#92;nabla u &#92;cdot &#92;nu&amp; = &#92;theta &#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} &amp; &#92;theta&#92;in&#92;mathbb{R} &#92;mbox{ 	(contact angle condition)}	&#92;&#92; f(u)u^{-1}&#92;;&#92;nabla &#92;Delta u &#92;cdot &#92;nu &amp; =0&#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} &amp; &#92;mbox{ no flux through the boundary} &#92;end{array}' class='latex' /></p>
<p>
As an introduction to his talk Antoine went through a rather insightful and brief heuristic derivation of this model, when <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bd%3D2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{d=2}' title='{d=2}' class='latex' /> this models the evolution of a <em>very thin film of liquid</em> spreading on top of a flat, horizontal surface. That this is more or less described by the above equation can be derived as follows: Let us think of the region <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5C%7B+%28x%2Cy%29%3A+0+%3C+y+%3C+u%28x%2Ct%29+%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;{ (x,y): 0 &lt; y &lt; u(x,t) &#92;}}' title='{&#92;{ (x,y): 0 &lt; y &lt; u(x,t) &#92;}}' class='latex' /> as the portion of space occupied by a thin drop at time <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bt%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{t}' title='{t}' class='latex' />, so <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%28x%2Ct%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u(x,t)}' title='{u(x,t)}' class='latex' /> represents the height of the drop at <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x}' title='{x}' class='latex' /> (a point on the flat surface) at time <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bt%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{t}' title='{t}' class='latex' />, and it is through <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> that we choose to keep track of the configuration of the liquid.</p>
<p>
The velocity of the fluid particles should not vary too much in the vertical direction (since the drop is assumed to be very thin), thus the flow of particles happens roughly only in horizontal directions. The same can be said about the fluid density, so the height <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> itself is a good measurement of mass density, under these circumstances then, conservation of mass gives us
<p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u_t%2B%5Cmbox%7Bdiv%7D+%5Cleft+%28u+v%5Cright+%29%3D0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u_t+&#92;mbox{div} &#92;left (u v&#92;right )=0' title='&#92;displaystyle u_t+&#92;mbox{div} &#92;left (u v&#92;right )=0' class='latex' /></p>
<p> where <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv%28x%2Ct%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v(x,t)}' title='{v(x,t)}' class='latex' /> denotes the <em>average horizontal speed</em> of the fluid lying over <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x}' title='{x}' class='latex' />. </p>
<p>
Under the physical assumption of a thin liquid this approximation is a valid one (and after all, the thinner the liquid the better this approximation works). With this in mind, the <em>contact angle condition</em> above</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla+u+%5Ccdot+%5Cnu+%3D+%5Ctheta+%5Cmbox%7B+on+%7D+%5Cpartial+%5C%7B+u%3E0%5C%7D+%5C%3B%5C%3B%5Cmbox%7B+where+%7D+%5Cnu%5Cmbox%7B+is+the+inner+normal%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;nabla u &#92;cdot &#92;nu = &#92;theta &#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} &#92;;&#92;;&#92;mbox{ where } &#92;nu&#92;mbox{ is the inner normal}' title='&#92;displaystyle &#92;nabla u &#92;cdot &#92;nu = &#92;theta &#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} &#92;;&#92;;&#92;mbox{ where } &#92;nu&#92;mbox{ is the inner normal}' class='latex' /></p>
<p>
says that the angle at which the liquid meets the planar surface is constant, this is an equilibrium condition stemming from the balance of interfacial forces of the drop and the flat surface (i.e. the constant is dictated by the chemistry of liquid and the surface and it is given a priori). By the way, the boundary <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cpartial+%5C%7B+u%3E0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;partial &#92;{ u&gt;0&#92;}}' title='{&#92;partial &#92;{ u&gt;0&#92;}}' class='latex' /> which is where this contact condition is given is a <em>free boundary</em> which in this model is usually called <em>the contact line</em>.</p>
<p>
To complete this heuristic derivation of the model, we need to specify how is the vector field <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv%28x%2Ct%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v(x,t)}' title='{v(x,t)}' class='latex' /> related to the drop represented by <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' />. The liquid in such a thin film is likely irrotational, so it&#8217;s not surprising there is a form of Darcy&#8217;s law, which in this case is
<p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+v%28x%2Ct%29%3D+-h%28u%29%5Cnabla+p%28x%2Ct%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle v(x,t)= -h(u)&#92;nabla p(x,t)' title='&#92;displaystyle v(x,t)= -h(u)&#92;nabla p(x,t)' class='latex' /></p>
<p>
where typically <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bh%28u%29%5Csim+u%5Em%3E0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{h(u)&#92;sim u^m&gt;0}' title='{h(u)&#92;sim u^m&gt;0}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bp%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{p}' title='{p}' class='latex' /> is the pressure, which by the <a class="snap_noshots" href="http://en.wikipedia.org/wiki/Young-Laplace_equation">Young-Laplace law</a> is proportional to the mean curvature of the film surface. As our drop of liquid is assumed to be very flat, </p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+p+%3D+-%5Csigma+%5CDelta+u&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle p = -&#92;sigma &#92;Delta u' title='&#92;displaystyle p = -&#92;sigma &#92;Delta u' class='latex' /></p>
<p>
gives a good approximation to the Young-Laplace law. This explains the appearance of the term <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28u%29%5Cnabla+%5CDelta+u%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(u)&#92;nabla &#92;Delta u}' title='{f(u)&#92;nabla &#92;Delta u}' class='latex' />, where <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28u%29%3D%5Csigma+h%28u%29+u%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(u)=&#92;sigma h(u) u}' title='{f(u)=&#92;sigma h(u) u}' class='latex' />, moreover since we were assuming <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv+%5Ccdot+%5Cnu+%3D+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v &#92;cdot &#92;nu = 0}' title='{v &#92;cdot &#92;nu = 0}' class='latex' /> (no flux at the fixed boundary) this justifies referring to the condition</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+f%28u%29u%5E%7B-1%7D%28%5Cnabla+%5CDelta+u+%29+%5Ccdot+%5Cnu+%3D+-h%28u%29+%5Cnabla+p+%5Ccdot+%5Cnu+%3D+v+%5Ccdot+%5Cnu+%3D+0+&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;displaystyle f(u)u^{-1}(&#92;nabla &#92;Delta u ) &#92;cdot &#92;nu = -h(u) &#92;nabla p &#92;cdot &#92;nu = v &#92;cdot &#92;nu = 0 ' title='&#92;displaystyle f(u)u^{-1}(&#92;nabla &#92;Delta u ) &#92;cdot &#92;nu = -h(u) &#92;nabla p &#92;cdot &#92;nu = v &#92;cdot &#92;nu = 0 ' class='latex' /></p>
<p>
as a &#8220;no flux through the boundary&#8221; condition.</p>
<p>
Recapitulating, the equations are (<img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Ctheta+%3E0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;theta &gt;0}' title='{&#92;theta &gt;0}' class='latex' /> is fixed) <a name="eqnThinFilmEqn">
<p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cleft.+%5Cbegin%7Barray%7D%7Brl%7D+u_t%2B%5Cmbox%7Bdiv%7D%28f%28u%29%5Cnabla+%5CDelta+u%29+%26+%3D0+%5C%5C+%5Cnabla+u+%5Ccdot+%5Cnu%26+%3D+%5Ctheta+%5C%3B%5C%3B%5Cmbox%7B+on+%7D+%5Cpartial+%5C%7B+u%3E0%5C%7D+%09%5C%5C+f%28u%29u%5E%7B-1%7D%5C%3B%5Cnabla+%5CDelta+u+%5Ccdot+%5Cnu+%26+%3D0%5C%3B%5C%3B%5Cmbox%7B+on+%7D+%5Cpartial+%5C%7B+u%3E0%5C%7D+%5Cend%7Barray%7D%5Cright+%5C%7D+%5C+%5C+%5C+%5C+%5C+%281%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left. &#92;begin{array}{rl} u_t+&#92;mbox{div}(f(u)&#92;nabla &#92;Delta u) &amp; =0 &#92;&#92; &#92;nabla u &#92;cdot &#92;nu&amp; = &#92;theta &#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} 	&#92;&#92; f(u)u^{-1}&#92;;&#92;nabla &#92;Delta u &#92;cdot &#92;nu &amp; =0&#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} &#92;end{array}&#92;right &#92;} &#92; &#92; &#92; &#92; &#92; (1)' title='&#92;displaystyle &#92;left. &#92;begin{array}{rl} u_t+&#92;mbox{div}(f(u)&#92;nabla &#92;Delta u) &amp; =0 &#92;&#92; &#92;nabla u &#92;cdot &#92;nu&amp; = &#92;theta &#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} 	&#92;&#92; f(u)u^{-1}&#92;;&#92;nabla &#92;Delta u &#92;cdot &#92;nu &amp; =0&#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;} &#92;end{array}&#92;right &#92;} &#92; &#92; &#92; &#92; &#92; (1)' class='latex' /></p>
<p></a></p>
<p>
A remarkable feature of these equations is that the fact that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%280%29%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(0)=0}' title='{f(0)=0}' class='latex' /> has a regularizing effect, namely: <em>linear</em> higher order parabolic equations (in particular, 4th order equations like <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_t%2B%28-1%29%5Em%5CDelta%5Em+u+%3D+0%5C%3B%5C%3Bm%3D2%2C3%2C...%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_t+(-1)^m&#92;Delta^m u = 0&#92;;&#92;;m=2,3,...}' title='{u_t+(-1)^m&#92;Delta^m u = 0&#92;;&#92;;m=2,3,...}' class='latex' />) do not have a comparison principle and in particular positive initial data could later on <em>change sign</em>. However, the non-linear equation <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_t%2B%5Cmbox%7Bdiv%7D%5Cleft+%28+f%28u%29+%5Cnabla+%5CDelta+u+%5Cright+%29+%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_t+&#92;mbox{div}&#92;left ( f(u) &#92;nabla &#92;Delta u &#92;right ) =0}' title='{u_t+&#92;mbox{div}&#92;left ( f(u) &#92;nabla &#92;Delta u &#92;right ) =0}' class='latex' /> preserves positivity as long as <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28u%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(u)}' title='{f(u)}' class='latex' /> vanishes fast enough as <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu+%5Crightarrow+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u &#92;rightarrow 0}' title='{u &#92;rightarrow 0}' class='latex' />. This was discovered first by <a class="snap_noshots" href="http://www.sciencedirect.com/science?_ob=ArticleURL&amp;_udi=B6WJ2-4CRM9F3-Y4&amp;_user=8442934&amp;_coverDate=01%2F31%2F1990&amp;_rdoc=1&amp;_fmt=high&amp;_orig=gateway&amp;_origin=gateway&amp;_sort=d&amp;_docanchor=&amp;view=c&amp;_searchStrId=1679743856&amp;_rerunOrigin=scholar.google&amp;_acct=C000057778&amp;_version=1&amp;_urlVersion=0&amp;_userid=8442934&amp;md5=b08479794736b074cac9eb11deaf095d&amp;searchtype=a">Bernis and Friedman in 1990</a>.</p>
<p>
<b>Theorem</b> [Bernis-Friedman '90]</p>
<p>
<em> If <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28u%29%3Du%5En%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(u)=u^n}' title='{f(u)=u^n}' class='latex' />, <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bn%3E1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{n&gt;1}' title='{n&gt;1}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_0+%5Cin+H%5E1%28%5Cmathbb%7BR%7D%5E1%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_0 &#92;in H^1(&#92;mathbb{R}^1)}' title='{u_0 &#92;in H^1(&#92;mathbb{R}^1)}' class='latex' /> with <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_0%5Cgeq+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_0&#92;geq 0}' title='{u_0&#92;geq 0}' class='latex' /> then the unique solution to (<a href="#eqnThinFilmEqn">1</a>) stays positive for all times.</em></p>
<p>
The essence of their proof comes down to an Entropy method: they observed that if one lets <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BG%3A%5Cmathbb%7BR%7D_%2B%5Crightarrow%5Cmathbb%7BR%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{G:&#92;mathbb{R}_+&#92;rightarrow&#92;mathbb{R}}' title='{G:&#92;mathbb{R}_+&#92;rightarrow&#92;mathbb{R}}' class='latex' /> be defined by</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+G%27%27%28s%29%3D%5Cfrac%7B1%7D%7Bf%28s%29%7D%2C+G%27%28A%29%3DG%28A%29%3D0+%5C%3B%5C%3B%5Cmbox%7B+for+some+%7D+A%3E0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle G&#039;&#039;(s)=&#92;frac{1}{f(s)}, G&#039;(A)=G(A)=0 &#92;;&#92;;&#92;mbox{ for some } A&gt;0' title='&#92;displaystyle G&#039;&#039;(s)=&#92;frac{1}{f(s)}, G&#039;(A)=G(A)=0 &#92;;&#92;;&#92;mbox{ for some } A&gt;0' class='latex' /></p>
<p>
then for any classical solution <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%28x%2Ct%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u(x,t)}' title='{u(x,t)}' class='latex' /> of (<a href="#eqnThinFilmEqn">1</a>) one has the energy equality </p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+T%3Et+%5CRightarrow+%5Cint+G%28u%28x%2CT%29%29+dx-%5Cint+G%28u%28x%2Ct%29%29dx+%3D+-%5Cint_t%5ET%5Cint+%7C%5CDelta+u%28x%2Ct%29%7C%5E2dxdt+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle T&gt;t &#92;Rightarrow &#92;int G(u(x,T)) dx-&#92;int G(u(x,t))dx = -&#92;int_t^T&#92;int |&#92;Delta u(x,t)|^2dxdt ' title='&#92;displaystyle T&gt;t &#92;Rightarrow &#92;int G(u(x,T)) dx-&#92;int G(u(x,t))dx = -&#92;int_t^T&#92;int |&#92;Delta u(x,t)|^2dxdt ' class='latex' /></p>
<p>
Therefore <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bt+%5Crightarrow+%5Cint+G%28u%28x%2Ct%29%29dx%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{t &#92;rightarrow &#92;int G(u(x,t))dx}' title='{t &#92;rightarrow &#92;int G(u(x,t))dx}' class='latex' /> is a monotone quantity (thus the name entropy). In particular, if it is bounded for the initial data then it ought to be bounded for all later times, and since <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bn+%3E+1+%5CRightarrow+G%28s%29+%5Crightarrow+%2B%5Cinfty%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{n &gt; 1 &#92;Rightarrow G(s) &#92;rightarrow +&#92;infty}' title='{n &gt; 1 &#92;Rightarrow G(s) &#92;rightarrow +&#92;infty}' class='latex' /> as <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bs+%5Crightarrow+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{s &#92;rightarrow 0}' title='{s &#92;rightarrow 0}' class='latex' /> the function <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%28x%2Ct%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u(x,t)}' title='{u(x,t)}' class='latex' /> cannot stick too much too zero or else the Entropy would blow up!.</p>
<p>
This shows that if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_0+%5Cgeq+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_0 &#92;geq 0}' title='{u_0 &#92;geq 0}' class='latex' /> then the solution with initial data <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_%5Cdelta+%3A%3D+u_0%2B%5Cdelta%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_&#92;delta := u_0+&#92;delta}' title='{u_&#92;delta := u_0+&#92;delta}' class='latex' /> remains positive for all later times, and taking <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cdelta+%5Crightarrow+0%5E%2B%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;delta &#92;rightarrow 0^+}' title='{&#92;delta &#92;rightarrow 0^+}' class='latex' /> they conclude that the solution <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%28x%2Ct%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u(x,t)}' title='{u(x,t)}' class='latex' /> with initial data <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_0%28x%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_0(x)}' title='{u_0(x)}' class='latex' /> stays non-negative for all later times.</p>
<p>
For the full details of the argument, see the paper of Bernis and Friedman. They consider explicitly only dimension <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bd%3D1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{d=1}' title='{d=1}' class='latex' />, but many of their results hold in higher space dimensions as well. Certainly, their idea of using an Entropy to obtain positivity ( pointwise information) is very useful in many other contexts.<br />
 The solutions produced by the Bernis-Friedman method all satisfy the <em>zero</em> contact angle condition, namely <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Ctheta+%3D+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;theta = 0}' title='{&#92;theta = 0}' class='latex' /> in</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla+u+%5Ccdot+%5Cnu+%3D+%5Ctheta+%5C%3B%5C%3B%5Cmbox%7B+on+%7D+%5Cpartial+%5C%7B+u%3E0%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;nabla u &#92;cdot &#92;nu = &#92;theta &#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;}' title='&#92;displaystyle &#92;nabla u &#92;cdot &#92;nu = &#92;theta &#92;;&#92;;&#92;mbox{ on } &#92;partial &#92;{ u&gt;0&#92;}' class='latex' /></p>
<p> The non-zero contact angle condition corresponds to the so-called partial wetting regime. For this case an approach developed by <a class="snap_noshots" href="http://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.36.4493">Felix Otto</a> relies on the fact that the dynamics are described by the gradient flow induced via the Wasserstein distance by the Energy functional</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cmathcal%7BE%7D%28u%29%3D%5Cint+%5Cfrac%7B1%7D%7B2%7Du_x%5E2%2B%5Cchi_%7B%5C%7Bu%3E0%5C%7D%7Ddx&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;mathcal{E}(u)=&#92;int &#92;frac{1}{2}u_x^2+&#92;chi_{&#92;{u&gt;0&#92;}}dx' title='&#92;displaystyle &#92;mathcal{E}(u)=&#92;int &#92;frac{1}{2}u_x^2+&#92;chi_{&#92;{u&gt;0&#92;}}dx' class='latex' /></p>
<p>
However, this approach is only known to work for <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28u%29%3Du%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(u)=u}' title='{f(u)=u}' class='latex' />. Antoine explained yet a third possible method to produce solutions which can handle <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28u%29%3Du%5En%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(u)=u^n}' title='{f(u)=u^n}' class='latex' /> for <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bn+%5Cin+%5B1%2C2%5D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{n &#92;in [1,2]}' title='{n &#92;in [1,2]}' class='latex' />. It also uses a variational formulation, the idea is to take the functional above and approximate it by a regularized energy</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cmathcal%7BE%7D_%5Cepsilon%28u%29%3D%5Cint+%5Cfrac%7B1%7D%7B2%7Du_x%5E2%2BQ_%5Cepsilon%28u%29dx%2C%5C%3B%5C%3B+Q_%5Cepsilon%28u%29+%5Crightarrow+%5Cchi_%7B%5C%7Bu%3E0%5C%7D%7D+%5Cmbox%7B+as+%7D+%5Cepsilon+%5Crightarrow+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;mathcal{E}_&#92;epsilon(u)=&#92;int &#92;frac{1}{2}u_x^2+Q_&#92;epsilon(u)dx,&#92;;&#92;; Q_&#92;epsilon(u) &#92;rightarrow &#92;chi_{&#92;{u&gt;0&#92;}} &#92;mbox{ as } &#92;epsilon &#92;rightarrow 0' title='&#92;displaystyle &#92;mathcal{E}_&#92;epsilon(u)=&#92;int &#92;frac{1}{2}u_x^2+Q_&#92;epsilon(u)dx,&#92;;&#92;; Q_&#92;epsilon(u) &#92;rightarrow &#92;chi_{&#92;{u&gt;0&#92;}} &#92;mbox{ as } &#92;epsilon &#92;rightarrow 0' class='latex' /></p>
<p>
In this case, the dynamics are described by the equation</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u_t%2B%5Cleft+%5Bu%5En+%5Cleft+%28+u_%7Bxx%7D+-P_%5Cepsilon%28u%29+%5Cright+%29_x%29+%5Cright+%5D_x%3D0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u_t+&#92;left [u^n &#92;left ( u_{xx} -P_&#92;epsilon(u) &#92;right )_x) &#92;right ]_x=0' title='&#92;displaystyle u_t+&#92;left [u^n &#92;left ( u_{xx} -P_&#92;epsilon(u) &#92;right )_x) &#92;right ]_x=0' class='latex' /></p>
<p>
where <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BP_%5Cepsilon%28u%29%3D%5Cfrac%7B1%7D%7B%5Cepsilon%7DP%28u%2F%5Cepsilon%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{P_&#92;epsilon(u)=&#92;frac{1}{&#92;epsilon}P(u/&#92;epsilon)}' title='{P_&#92;epsilon(u)=&#92;frac{1}{&#92;epsilon}P(u/&#92;epsilon)}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BP%28s%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{P(s)}' title='{P(s)}' class='latex' /> is a kind of bump function which vanishes for <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bs+%5Cgeq+1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{s &#92;geq 1}' title='{s &#92;geq 1}' class='latex' />. It turns this approximation has a physical interpretation: the new pressure term <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BP_%5Cepsilon%28u%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{P_&#92;epsilon(u)}' title='{P_&#92;epsilon(u)}' class='latex' /> models the disjoining/cojoining intermorlecular forces affecting the triple junction of the fluid, air and solid (flat surface) phases. As <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cepsilon+%5Crightarrow+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;epsilon &#92;rightarrow 0}' title='{&#92;epsilon &#92;rightarrow 0}' class='latex' />, this approximation allowed Antoine to obtain a solution that satisfies a non-zero contact angle condition</p>
<p>
<b>Theorem</b>[Mellet '11]</p>
<p>
<em>If <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28s%29%5Csim+s%5En%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(s)&#92;sim s^n}' title='{f(s)&#92;sim s^n}' class='latex' /> for <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B0%5Cleq+u%3C%3C1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{0&#92;leq u&lt;&lt;1}' title='{0&#92;leq u&lt;&lt;1}' class='latex' />, <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bn%5Cin+%5B1%2C2%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{n&#92;in [1,2)}' title='{n&#92;in [1,2)}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28s%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(s)}' title='{f(s)}' class='latex' /> is <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^1}' title='{C^1}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28u%29%3E0%5C%3B%5Cforall+s%3E0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(u)&gt;0&#92;;&#92;forall s&gt;0}' title='{f(u)&gt;0&#92;;&#92;forall s&gt;0}' class='latex' /> then the approximating solutions <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_&#92;epsilon}' title='{u_&#92;epsilon}' class='latex' /> converge uniformly to a continuous function which solves in the sense of distributions</em></p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u_t%2B+%5Cleft+%5B+f%28u%29%09u_%7Bxxx%7D%5Cright+%5D%3D0+%5C%3B%5C%3B%5Cmbox%7B+in+%7D+%5C%7Bu%3E0%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u_t+ &#92;left [ f(u)	u_{xxx}&#92;right ]=0 &#92;;&#92;;&#92;mbox{ in } &#92;{u&gt;0&#92;}' title='&#92;displaystyle u_t+ &#92;left [ f(u)	u_{xxx}&#92;right ]=0 &#92;;&#92;;&#92;mbox{ in } &#92;{u&gt;0&#92;}' class='latex' /></p>
<p>
<em>moreover, for almost every <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bt%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{t}' title='{t}' class='latex' /> if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x}' title='{x}' class='latex' /> is the smallest or the largest point in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cpartial+%5C%7Bu%3E0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;partial &#92;{u&gt;0&#92;}}' title='{&#92;partial &#92;{u&gt;0&#92;}}' class='latex' /> then</em></p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7B2%7Du_x%5E2%28x%2Ct%29%3D1+%5Cmbox%7B+%28non-zero+contact+angle%29+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;frac{1}{2}u_x^2(x,t)=1 &#92;mbox{ (non-zero contact angle) }' title='&#92;displaystyle &#92;frac{1}{2}u_x^2(x,t)=1 &#92;mbox{ (non-zero contact angle) }' class='latex' /></p>
<p>
<em>and for the other points <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx+%5Cin+%5Cpartial+%5C%7Bu%3E0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x &#92;in &#92;partial &#92;{u&gt;0&#92;}}' title='{x &#92;in &#92;partial &#92;{u&gt;0&#92;}}' class='latex' /> all we can say is that the contact angle condition is the same on the end points of each bounded, connected component of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5C%7Bu%3D0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;{u=0&#92;}}' title='{&#92;{u=0&#92;}}' class='latex' />.</em></p>
<p>
This last property of the solution has to do with the lack of continuity of the energy functional with respect to just uniform convergence, but I will not go into that in detail here for lack of time.</p>
<p>
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			<media:title type="html">Nestor</media:title>
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		<title>MSRI Workshop, Day 1: Unique continuation for Nonlinear PDEs</title>
		<link>https://partialdifferentialequations.wordpress.com/2011/03/08/msri-workshop-day-1-unique-continuation-for-nonlinear-pdes/</link>
		<comments>https://partialdifferentialequations.wordpress.com/2011/03/08/msri-workshop-day-1-unique-continuation-for-nonlinear-pdes/#comments</comments>
		<pubDate>Tue, 08 Mar 2011 16:51:45 +0000</pubDate>
		<dc:creator>Nestor</dc:creator>
				<category><![CDATA[Fully non linear equations]]></category>

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		<description><![CDATA[This week MSRI is a rather busy place, as the flagship workshop of the program on Free boundary problems is taking place. Luis Silvestre (who happens to be my mathematical older brother) gave a talk this monday on his very recent work with Scott Armstrong, which deals with unique continuation for nonlinear elliptic PDEs, this post is an [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=659&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><!-- p.p1 {margin: 0.0px 0.0px 12.0px 0.0px; font: 12.0px Times} p.p2 {margin: 0.0px 0.0px 12.0px 0.0px; font: 12.0px Times; min-height: 14.0px} p.p3 {margin: 0.0px 0.0px 12.0px 0.0px; text-align: center; font: 12.0px Times} span.s1 {text-decoration: underline ; color: #2a2bee} -->This week MSRI is a rather busy place, as the flagship workshop of the program on <a href="http://www.msri.org/web/msri/scientific/workshops/show/-/event/Wm537">Free boundary problems</a> is taking place. <a href="http://www.math.uchicago.edu/~luis/">Luis Silvestre</a> (who happens to be my mathematical older brother) gave a talk this monday on his very recent work with <a href="http://math.uchicago.edu/~armstrong/">Scott Armstrong</a>, which deals with unique continuation for nonlinear elliptic PDEs, this post is an overview of his talk. A preprint of their work is available on the <a href="http://arxiv.org/abs/1102.1673">arxiv</a>.</p>
<p>As usual, any potential mistakes and inaccuracies in the presentation below are due to the author of this post and shouldn&#8217;t reflect on what was a terrific lecture by Luis.</p>
<p>The main question stems from the analytic continuation property for Laplace&#8217;s equation <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5CDelta+u+%3D+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Delta u = 0}' title='{&#92;Delta u = 0}' class='latex' />, which is a very well known classical fact. A fact which however, is not &#8220;so easy&#8221; to prove. Classically, it says the following, let us put for a second <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BLu%3D%5CDelta+u%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{Lu=&#92;Delta u}' title='{Lu=&#92;Delta u}' class='latex' /> then &#8220;unique continuation&#8221; refers to the following fact:</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cmbox%7B+if+%7D+L+u+%3D+0+%5Cmbox%7B+in+some+open+set+%7D+%5COmega+%5C%3B%5Cmbox%7B+and+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;mbox{ if } L u = 0 &#92;mbox{ in some open set } &#92;Omega &#92;;&#92;mbox{ and }' title='&#92;displaystyle &#92;mbox{ if } L u = 0 &#92;mbox{ in some open set } &#92;Omega &#92;;&#92;mbox{ and }' class='latex' /></p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5C%7Bu%3D0%5C%7D+%5Cmbox%7B+has+non-empty+interior%2C+then+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;{u=0&#92;} &#92;mbox{ has non-empty interior, then }' title='&#92;displaystyle &#92;{u=0&#92;} &#92;mbox{ has non-empty interior, then }' class='latex' /></p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u+%5Cequiv+0+%5Cmbox%7B+in+%7D+%5COmega&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u &#92;equiv 0 &#92;mbox{ in } &#92;Omega' title='&#92;displaystyle u &#92;equiv 0 &#92;mbox{ in } &#92;Omega' class='latex' /></p>
<p><span id="more-659"></span></p>
<p>Note that since <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BL%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{L}' title='{L}' class='latex' /> is linear, this is equivalent to the following</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cmbox%7B+if+%7D+L+u+%3D+L+v+%5Cmbox%7B+in+some+open+set+%7D+%5COmega+%5C%3B%5Cmbox%7B+and+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;mbox{ if } L u = L v &#92;mbox{ in some open set } &#92;Omega &#92;;&#92;mbox{ and }' title='&#92;displaystyle &#92;mbox{ if } L u = L v &#92;mbox{ in some open set } &#92;Omega &#92;;&#92;mbox{ and }' class='latex' /></p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5C%7Bu%3Dv%5C%7D+%5Cmbox%7B+has+non-empty+interior%2C+then+%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;{u=v&#92;} &#92;mbox{ has non-empty interior, then }' title='&#92;displaystyle &#92;{u=v&#92;} &#92;mbox{ has non-empty interior, then }' class='latex' /></p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u+%5Cequiv+v+%5Cmbox%7B+in+%7D+%5COmega&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u &#92;equiv v &#92;mbox{ in } &#92;Omega' title='&#92;displaystyle u &#92;equiv v &#92;mbox{ in } &#92;Omega' class='latex' /></p>
<p>Luis claims that (as far as he knows) there are really only three ways to prove this:</p>
<p>1) By using the analyticity of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' />, which follows by the regularity of the equation (and this, in a sense, is kinda cheating).</p>
<p>2) One can also prove this via Carleman estimates (discovered by Carleman in 1939). See for instance works by <a href="http://math.berkeley.edu/~tataru">Daniel Tataru</a>, he has several expository notes about this in his <a href="http://math.berkeley.edu/~tataru/ucp.html">webpage</a>.</p>
<p>3) Using monotonicity formulas, such as Almgren&#8217;s frequency formula (this is an approach developed in series of collaborations by <a href="http://onlinelibrary.wiley.com/doi/10.1002/cpa.3160400305/abstract">N. Garofalo and F. Lin</a>).</p>
<p>In what sense is the first method kind of cheating? Well, analyticity is really strong and does not hold in many interesting problems. In contrast, the last two methods can handle <em>linear equations</em> with variable coefficients whose solutions are not necessarily analytic. Namely if consider the linear operator</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+Lu%3A%3D+Tr%28A%28x%29D%5E2u%29%2Bb%28x%29%5Ccdot+%5Cnabla+u+%2B+c%28x%29u%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle Lu:= Tr(A(x)D^2u)+b(x)&#92;cdot &#92;nabla u + c(x)u(x)' title='&#92;displaystyle Lu:= Tr(A(x)D^2u)+b(x)&#92;cdot &#92;nabla u + c(x)u(x)' class='latex' /></p>
<p>Then unique continuation holds if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BA%28x%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{A(x)}' title='{A(x)}' class='latex' /> is Lipschitz and uniformly elliptic and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bb%2Cc%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{b,c}' title='{b,c}' class='latex' /> are (say) bounded. Moreover, if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BA%28x%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{A(x)}' title='{A(x)}' class='latex' /> is slightly less than Lipschitz then unique continuation does not hold, as there are known counterexamples.</p>
<p>So for linear equations the story is rather complete. What about <strong>non-linear equations</strong>?</p>
<p>There are some 2-dimensional results, including for the <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bp%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{p}' title='{p}' class='latex' />-Laplacian: if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bp%3D1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{p=1}' title='{p=1}' class='latex' /> unique continuation does not hold, if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B1%3Cp%3C%5Cinfty%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{1&lt;p&lt;&#92;infty}' title='{1&lt;p&lt;&#92;infty}' class='latex' /> it has been proven (again, only in 2d). For the <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cinfty%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;infty}' title='{&#92;infty}' class='latex' />-Laplacian is not known even in 2d.</p>
<p>We will preoccupy ourselves with the case of Fully non-linear equations</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+F%3DF%28D%5E2u%29%3D0%5C%3B%5C%3BF%3A+S_%7Bn%5Ctimes+n%7D+%5Crightarrow+%5Cmathbb%7BR%7D%2C%5C%3B%5Cmbox%7Belliptic%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle F=F(D^2u)=0&#92;;&#92;;F: S_{n&#92;times n} &#92;rightarrow &#92;mathbb{R},&#92;;&#92;mbox{elliptic}' title='&#92;displaystyle F=F(D^2u)=0&#92;;&#92;;F: S_{n&#92;times n} &#92;rightarrow &#92;mathbb{R},&#92;;&#92;mbox{elliptic}' class='latex' /></p>
<p>where <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is a weak solution in the Crandall-Lions &#8220;viscosity&#8221; sense. If we assume enough things about <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> (say <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> is convex and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B1%2C1%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{1,1}}' title='{C^{1,1}}' class='latex' />) then unique continuation is true. Why?</p>
<p>Since <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> convex, the Evans-Krylov theorem says that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B2%2C%5Calpha%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{2,&#92;alpha}}' title='{C^{2,&#92;alpha}}' class='latex' /> for some <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Calpha%3E0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;alpha&gt;0}' title='{&#92;alpha&gt;0}' class='latex' />. Then, since <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> is <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B1%2C1%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{1,1}}' title='{C^{1,1}}' class='latex' /> we can differentiate the equation and see that the derivatives solve a linear equation with Lipschitz coefficients and thus we can apply the linear result to the linearized equation.</p>
<p>Therefore this case is a trivial application of the linear result and the regularity for the equation. In particular, since it reduces to the linear case, it proves both formulations of unique continuation which are not necessarily equivalent for non-linear equations since its no longer true that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%28u%29%3DF%28v%29%5CRightarrow+F%28u-v%29%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F(u)=F(v)&#92;Rightarrow F(u-v)=0}' title='{F(u)=F(v)&#92;Rightarrow F(u-v)=0}' class='latex' />. However, if we remove any of the assumptions (convexity, <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B1%2C1%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{1,1}}' title='{C^{1,1}}' class='latex' /> regularity of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' />) the proof no longer works: convexity was needed to guarantee existence of classical solutions by the Evans-Krylov Theorem, and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B1%2C1%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{1,1}}' title='{C^{1,1}}' class='latex' /> regularity was required to apply the linear theorem after taking derivatives.</p>
<p>If we could remove any of them it would be interesting because (for instance) we could then prove unique continuation for the Pucci operators:</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+P%5E%2B_%7B%5Clambda%2C%5CLambda%7D%28D%5E2u%29%3D+%5Csup+%5Climits_%7B%5Clambda+%5Cleq+A+%5Cleq+%5CLambda%7D+%5Cmbox%7BTr%7D%28A+%5Ccdot+D%5E2u%29+%3D+%5CLambda%5C%3B+%5Cmbox%7BTr%7D%28%28D%5E2u%29%5E%2B%29%2B%5Clambda%5C%3B+%5Cmbox%7BTr%7D%28%28D%5E2u%29%5E-%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle P^+_{&#92;lambda,&#92;Lambda}(D^2u)= &#92;sup &#92;limits_{&#92;lambda &#92;leq A &#92;leq &#92;Lambda} &#92;mbox{Tr}(A &#92;cdot D^2u) = &#92;Lambda&#92;; &#92;mbox{Tr}((D^2u)^+)+&#92;lambda&#92;; &#92;mbox{Tr}((D^2u)^-)' title='&#92;displaystyle P^+_{&#92;lambda,&#92;Lambda}(D^2u)= &#92;sup &#92;limits_{&#92;lambda &#92;leq A &#92;leq &#92;Lambda} &#92;mbox{Tr}(A &#92;cdot D^2u) = &#92;Lambda&#92;; &#92;mbox{Tr}((D^2u)^+)+&#92;lambda&#92;; &#92;mbox{Tr}((D^2u)^-)' class='latex' /></p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+P%5E-_%7B%5Clambda%2C%5CLambda%7D%28D%5E2u%29%3D+%5Cinf+%5Climits_%7B%5Clambda+%5Cleq+A+%5Cleq+%5CLambda%7D+%5Cmbox%7BTr%7D%28A+%5Ccdot+D%5E2u%29+%3D%5Clambda%5C%3B+%5Cmbox%7BTr%7D%28%28D%5E2u%29%5E%2B%29%2B%5CLambda%5C%3B+%5Cmbox%7BTr%7D%28%28D%5E2u%29%5E-%29+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle P^-_{&#92;lambda,&#92;Lambda}(D^2u)= &#92;inf &#92;limits_{&#92;lambda &#92;leq A &#92;leq &#92;Lambda} &#92;mbox{Tr}(A &#92;cdot D^2u) =&#92;lambda&#92;; &#92;mbox{Tr}((D^2u)^+)+&#92;Lambda&#92;; &#92;mbox{Tr}((D^2u)^-) ' title='&#92;displaystyle P^-_{&#92;lambda,&#92;Lambda}(D^2u)= &#92;inf &#92;limits_{&#92;lambda &#92;leq A &#92;leq &#92;Lambda} &#92;mbox{Tr}(A &#92;cdot D^2u) =&#92;lambda&#92;; &#92;mbox{Tr}((D^2u)^+)+&#92;Lambda&#92;; &#92;mbox{Tr}((D^2u)^-) ' class='latex' /></p>
<p>Here <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%28M%29%5E%7B%5Cpm%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{(M)^{&#92;pm}}' title='{(M)^{&#92;pm}}' class='latex' /> denotes the projection of a symmetric matrix <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BM%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{M}' title='{M}' class='latex' /> to the subspaces where it is positive or negative define.</p>
<p>The result of Silvestre and Armstrong consists in removing the condition that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> is convex and prove unique continuation for a single <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> as long as <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> is <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B1%2C1%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{1,1}}' title='{C^{1,1}}' class='latex' />. namely:</p>
<p><strong>Theorem </strong>[Armstrong-Silvestre '10 <a href="http://arxiv.org/abs/1102.1673">(arxiv)</a>]</p>
<p><em>Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> be a <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B1%2C1%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{1,1}}' title='{C^{1,1}}' class='latex' /> function in the space of symmetric matrices giving rise to a uniformly elliptic equation and let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> be a viscosity solution of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%28D%5E2u%29%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F(D^2u)=0}' title='{F(D^2u)=0}' class='latex' /> in some open set <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Omega}' title='{&#92;Omega}' class='latex' />. Then</em></p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5C%7Bu%3D0%5C%7D+%5Cmbox%7B+%5Cemph%7Bhas+non-empty+interior%7D+%7D+%5CRightarrow+u+%5Cequiv+0+%5Cmbox%7B+in+%7D+%5COmega&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;{u=0&#92;} &#92;mbox{ &#92;emph{has non-empty interior} } &#92;Rightarrow u &#92;equiv 0 &#92;mbox{ in } &#92;Omega' title='&#92;displaystyle &#92;{u=0&#92;} &#92;mbox{ &#92;emph{has non-empty interior} } &#92;Rightarrow u &#92;equiv 0 &#92;mbox{ in } &#92;Omega' class='latex' /></p>
<p>To fix ideas, let us see how Harnack inequality says that if unique continuation does not hold then the counterexample is going to be very hard to build&#8230;</p>
<p>For suppose you had a <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> that violates unique continuation, if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> had a sign in some neighborhood of a point of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cpartial+%5C%7Bu%3D0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;partial &#92;{u=0&#92;}}' title='{&#92;partial &#92;{u=0&#92;}}' class='latex' /> then by Harnack inequality</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Csup+%5Climits_%7BB_%7Br%2F2%7D%7D+u+%5Cleq+C+%5Cinf+%5Climits_%7BB_%7B1%2F2%7D%7D+u+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;sup &#92;limits_{B_{r/2}} u &#92;leq C &#92;inf &#92;limits_{B_{1/2}} u = 0' title='&#92;displaystyle &#92;sup &#92;limits_{B_{r/2}} u &#92;leq C &#92;inf &#92;limits_{B_{1/2}} u = 0' class='latex' /></p>
<p>thus, the <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> that violates unique continuation must change sign <em>in every neighborhood of every point in</em> <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cpartial+%5C%7B+u+%3D0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;partial &#92;{ u =0&#92;}}' title='{&#92;partial &#92;{ u =0&#92;}}' class='latex' /> !.</p>
<p>Let us give a sketch of their proof: <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5C%7Bu%3D0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;{u=0&#92;}}' title='{&#92;{u=0&#92;}}' class='latex' /> has non-empty interior, so it contains some little ball <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B}' title='{B}' class='latex' />. Let us translate this ball inside <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5C%7Bu%3D0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;{u=0&#92;}}' title='{&#92;{u=0&#92;}}' class='latex' /> until it touches the boundary of the positivity set <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5C%7Bu%3E0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;{u&gt;0&#92;}}' title='{&#92;{u&gt;0&#92;}}' class='latex' /> from outside.</p>
<p>Now note that since <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> might not be convex, all the regularity we know of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B1%2C%5Calpha%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{1,&#92;alpha}}' title='{C^{1,&#92;alpha}}' class='latex' /> (by Krylov-Safonov plus translation invariance of the equation). However, the assumption that this ball <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B}' title='{B}' class='latex' /> touches from outside is very strong, and in particular as we are about to see <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> will be <em>classical</em> in a neighborhood of that point, which effectively allows us to work around the lack of an Evans-Krylov theorem for non-convex equations. To see <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is classical near the contact point we proceed in a couple of steps:</p>
<p><strong>Step 1</strong>. We are going to show that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> grows better than quadratically away from the point <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx_0+%5Cin+%5Cpartial+B+%5Ccap+%5Cpartial+%5C%7Bu%3D0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x_0 &#92;in &#92;partial B &#92;cap &#92;partial &#92;{u=0&#92;}}' title='{x_0 &#92;in &#92;partial B &#92;cap &#92;partial &#92;{u=0&#92;}}' class='latex' />. Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv%3Du_e%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v=u_e}' title='{v=u_e}' class='latex' />, then <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v}' title='{v}' class='latex' /> solves</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cmbox%7BTr%7D%28A%28x%29D%5E2v%29%3D0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;mbox{Tr}(A(x)D^2v)=0' title='&#92;displaystyle &#92;mbox{Tr}(A(x)D^2v)=0' class='latex' /></p>
<p>for some <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BA%28x%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{A(x)}' title='{A(x)}' class='latex' /> which is bounded measurable and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Clambda+I+%5Cleq+A+%5Cleq+%5CLambda+I%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;lambda I &#92;leq A &#92;leq &#92;Lambda I}' title='{&#92;lambda I &#92;leq A &#92;leq &#92;Lambda I}' class='latex' />. Therefore, we can apply the boundary Harnack principle for non-divergence form equations (cf. Gilbarg-Trudinger section 9.9, second edition) to get</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bv%28x%29%7D%7Bd%28x%2C%5Cpartial+B%29%7D%5Cin+C%5E%5Calpha+%5C%3B%5C%3B%5C%3B%5Cmbox%7B+near+%7D+x_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;frac{v(x)}{d(x,&#92;partial B)}&#92;in C^&#92;alpha &#92;;&#92;;&#92;;&#92;mbox{ near } x_0' title='&#92;displaystyle &#92;frac{v(x)}{d(x,&#92;partial B)}&#92;in C^&#92;alpha &#92;;&#92;;&#92;;&#92;mbox{ near } x_0' class='latex' /></p>
<p>So <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v}' title='{v}' class='latex' /> looks almost as if it were <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B1%2C%5Calpha%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{1,&#92;alpha}}' title='{C^{1,&#92;alpha}}' class='latex' /> near <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx_0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x_0}' title='{x_0}' class='latex' />. Thus</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+v%28x%29%3D+b+%5Ccdot+%28x-x_0%29%2BO%28%7Cx-x_0%7C%5E%7B1%2B%5Calpha%7D%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle v(x)= b &#92;cdot (x-x_0)+O(|x-x_0|^{1+&#92;alpha})' title='&#92;displaystyle v(x)= b &#92;cdot (x-x_0)+O(|x-x_0|^{1+&#92;alpha})' class='latex' /></p>
<p>Now observe that since <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx_0+%5Cin+%5Cpartial+%5C%7Bu+%3D+0%5C%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x_0 &#92;in &#92;partial &#92;{u = 0&#92;}}' title='{x_0 &#92;in &#92;partial &#92;{u = 0&#92;}}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cnabla+u%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;nabla u}' title='{&#92;nabla u}' class='latex' /> vanishes in <img src='https://s-ssl.wordpress.com/latex.php?latex=B&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='B' title='B' class='latex' /> we must have <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bb%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{b=0}' title='{b=0}' class='latex' />. Since this works for every directional derivative of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' />, this guarantees that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> grows like  <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BO%28%7Cx-x_0%7C%5E%7B2%2B%5Calpha%7D%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{O(|x-x_0|^{2+&#92;alpha})}' title='{O(|x-x_0|^{2+&#92;alpha})}' class='latex' /> near <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx_0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x_0}' title='{x_0}' class='latex' />. In particular, <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BD%5E2u%28x_0%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{D^2u(x_0)}' title='{D^2u(x_0)}' class='latex' /> exists and must be <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{0}' title='{0}' class='latex' />.</p>
<p><strong>Step 2</strong>. The important thing is that the power is greater than <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{2}' title='{2}' class='latex' />, thus, if we rescale</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u%28x%29%3D%5Cfrac%7B1%7D%7Br%5E2%7Du%28x_0%2Brx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u(x)=&#92;frac{1}{r^2}u(x_0+rx)' title='&#92;displaystyle u(x)=&#92;frac{1}{r^2}u(x_0+rx)' class='latex' /></p>
<p>then <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%7Cu_r%28x%29%7C%5Cleq+Cr%5E%5Calpha%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{|u_r(x)|&#92;leq Cr^&#92;alpha}' title='{|u_r(x)|&#92;leq Cr^&#92;alpha}' class='latex' /> in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1}' title='{B_1}' class='latex' /> and also solve <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%28D%5E2u_r%29%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F(D^2u_r)=0}' title='{F(D^2u_r)=0}' class='latex' /> in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1}' title='{B_1}' class='latex' />. Then, if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Br%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{r}' title='{r}' class='latex' /> is very small, <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is going to be very flat in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1}' title='{B_1}' class='latex' /> so we may apply a <a href="http://www.math.columbia.edu/~savin/Small_pert.pdf">deep result of O. Savin</a> that then says that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_r%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_r}' title='{u_r}' class='latex' /> is <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B2%2C%5Calpha%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{2,&#92;alpha}}' title='{C^{2,&#92;alpha}}' class='latex' /> in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_%7B1%2F2%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_{1/2}}' title='{B_{1/2}}' class='latex' />. Rescaling back, we get</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u+%5Cin+C%5E%7B2%2C%5Calpha%7D%28B_r%28x_0%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u &#92;in C^{2,&#92;alpha}(B_r(x_0))' title='&#92;displaystyle u &#92;in C^{2,&#92;alpha}(B_r(x_0))' class='latex' /></p>
<p>This then has essentially worked around the lack of convexity in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' />, which is what we used first to get <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B2%2C%5Calpha%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{2,&#92;alpha}}' title='{C^{2,&#92;alpha}}' class='latex' /> and if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> is <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B1%2C1%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{1,1}}' title='{C^{1,1}}' class='latex' /> then we can argue as before and get the unique continuation by linearizing and applying the result for linear operators.</p>
<p>Remark: this proof will not work to prove that general unique continuation holds, i.e. if we instead have two viscosity solutions of the same equation in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1}' title='{B_1}' class='latex' /> which agree on a set with non-empty interior then we cant prove that they agree (if one of them is smooth enough though, these arguments will suffice).</p>
<p>This leads to the next part of Luis&#8217; talk, where he announced a new partial regularity result obtained with Scott Armstrong and <a href="http://www.math.nyu.edu/~csmart/">Charlie Smart</a>*. Namely, what is the size of the set of possible singularities for fully non-linear equations? As this result is still not published, I will only quote their main result, and go back to it in another post once their preprint becomes available in the next couple of weeks</p>
<p><strong>Theorem</strong> [Armstrong, Silvestre, Smart '11]</p>
<p><em>If <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%28D%5E2u%29%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F(D^2u)=0}' title='{F(D^2u)=0}' class='latex' /> in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1}' title='{B_1}' class='latex' />, <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{F}' title='{F}' class='latex' /> is uniformly elliptic and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^1}' title='{C^1}' class='latex' />, then there exists <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cepsilon%3D%5Cepsilon%28%5Clambda%2C%5CLambda%2Cn%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;epsilon=&#92;epsilon(&#92;lambda,&#92;Lambda,n)}' title='{&#92;epsilon=&#92;epsilon(&#92;lambda,&#92;Lambda,n)}' class='latex' /> such that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%7B2%2C%5Calpha%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^{2,&#92;alpha}}' title='{C^{2,&#92;alpha}}' class='latex' /> outside of a closed set of dimension at most <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bn-%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{n-&#92;epsilon}' title='{n-&#92;epsilon}' class='latex' /></em>.</p>
<p>*As Scott duly observed, his authorship of a several joint papers where the two other authors have last names starting with &#8220;S&#8221; might lead to rather amusing citations.</p>
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		<title>Update: Blog restarted, new name+new blog address!</title>
		<link>https://partialdifferentialequations.wordpress.com/2010/12/29/update-blog-restarted-new-name/</link>
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		<pubDate>Wed, 29 Dec 2010 06:28:58 +0000</pubDate>
		<dc:creator>Nestor</dc:creator>
				<category><![CDATA[quick posts]]></category>

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		<description><![CDATA[After an almost year long hiatus I am getting back into math blogging.  The new http address is a bit long but at least easy to remember! (turns out &#8220;pdeblog.wordpress.com&#8221; was already taken!) The old site will be up at least for a while, but all the old posts have been copied to this new [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=653&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>After an almost year long hiatus I am getting back into math blogging.  The new http address is a bit long but at least easy to remember! (turns out &#8220;pdeblog.wordpress.com&#8221; was already taken!)</p>
<p>The <a href="http://themathingpot.wordpress.com/">old site</a> will be up at least for a while, but all the old posts have been copied to this new blog. To reflect the fact that nearly all posts here have dealt with Partial  Differential Equations the new site will go by the name  “PDE Blog”.</p>
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		<title>Reviewing the regularity theory of elliptics PDEs via the Laplace equation. Part III. (representation formulas)</title>
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		<pubDate>Sat, 16 Jan 2010 03:33:04 +0000</pubDate>
		<dc:creator>Nestor</dc:creator>
				<category><![CDATA[Partial Differential Equations]]></category>
		<category><![CDATA[A priori estimates]]></category>
		<category><![CDATA[harmonic functions]]></category>
		<category><![CDATA[Harnack's inequality]]></category>
		<category><![CDATA[integral representation formulas]]></category>
		<category><![CDATA[Laplace equation]]></category>
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		<description><![CDATA[This is the third of a series of posts dealing with the regularity theory of elliptic equations. My motivation in writing these is outlined in the first post. The previous post is here. Let us recall Green&#8217;s identity, if are any functions smooth in and is a bounded domain with smooth boundary we have this [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=615&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
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This is the third of a series of posts dealing with the regularity theory of elliptic equations. My motivation in writing these is outlined in the <a class="snap_noshots" href="http://themathingpot.wordpress.com/2010/01/06/laplace/">first post</a>. The previous post is <a class="snap_noshots" href="http://themathingpot.wordpress.com/2010/01/06/laplaceii/">here</a>.</p>
<p>
Let us recall Green&#8217;s identity, if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%2Cv%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u,v}' title='{u,v}' class='latex' /> are any functions smooth in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cbar%7B%5COmega%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;bar{&#92;Omega}}' title='{&#92;bar{&#92;Omega}}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Omega}' title='{&#92;Omega}' class='latex' /> is a bounded domain with smooth boundary we have</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%5COmega+u%5CDelta+v+-+v+%5CDelta+u+dx+%3D+%5Cint_%7B%5Cpartial+%5COmega%7Du%5Cfrac%7B%5Cpartial+v%7D%7B%5Cpartial+%5Cnu%7D-v%5Cfrac%7B%5Cpartial+u%7D%7B%5Cpartial+%5Cnu%7DdS&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_&#92;Omega u&#92;Delta v - v &#92;Delta u dx = &#92;int_{&#92;partial &#92;Omega}u&#92;frac{&#92;partial v}{&#92;partial &#92;nu}-v&#92;frac{&#92;partial u}{&#92;partial &#92;nu}dS' title='&#92;displaystyle &#92;int_&#92;Omega u&#92;Delta v - v &#92;Delta u dx = &#92;int_{&#92;partial &#92;Omega}u&#92;frac{&#92;partial v}{&#92;partial &#92;nu}-v&#92;frac{&#92;partial u}{&#92;partial &#92;nu}dS' class='latex' /></p>
<p>
this identity can be obtained with a couple of integration by parts involving the vector fields <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu+%5Cnabla+v%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u &#92;nabla v}' title='{u &#92;nabla v}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv+%5Cnabla+u%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v &#92;nabla u}' title='{v &#92;nabla u}' class='latex' />.</p>
<p>
Lets rewrite the identity as</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%5COmega+u%5CDelta+vdx+%3D+-%5Cint_%5COmega+v+%5CDelta+u+dx+%2B+%5Cint_%7B%5Cpartial+%5COmega%7Du%5Cfrac%7B%5Cpartial+v%7D%7B%5Cpartial+%5Cnu%7D-v%5Cfrac%7B%5Cpartial+u%7D%7B%5Cpartial+%5Cnu%7DdS&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_&#92;Omega u&#92;Delta vdx = -&#92;int_&#92;Omega v &#92;Delta u dx + &#92;int_{&#92;partial &#92;Omega}u&#92;frac{&#92;partial v}{&#92;partial &#92;nu}-v&#92;frac{&#92;partial u}{&#92;partial &#92;nu}dS' title='&#92;displaystyle &#92;int_&#92;Omega u&#92;Delta vdx = -&#92;int_&#92;Omega v &#92;Delta u dx + &#92;int_{&#92;partial &#92;Omega}u&#92;frac{&#92;partial v}{&#92;partial &#92;nu}-v&#92;frac{&#92;partial u}{&#92;partial &#92;nu}dS' class='latex' /></p>
<p>
thus, at least formally, if somehow we could find for every <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx+%5Cin+%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x &#92;in &#92;Omega}' title='{x &#92;in &#92;Omega}' class='latex' /> a function <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv_x%28y%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v_x(y)}' title='{v_x(y)}' class='latex' /> such that</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5CDelta+v_x%28y%29%3D%5Cdelta_x%28y%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;Delta v_x(y)=&#92;delta_x(y)' title='&#92;displaystyle &#92;Delta v_x(y)=&#92;delta_x(y)' class='latex' /></p>
<p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle++v_x%28y%29+%5Cequiv+0+%5Cmbox%7B+on+%7D+%5Cpartial+%5COmega&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle  v_x(y) &#92;equiv 0 &#92;mbox{ on } &#92;partial &#92;Omega' title='&#92;displaystyle  v_x(y) &#92;equiv 0 &#92;mbox{ on } &#92;partial &#92;Omega' class='latex' /></p>
<p>
then Green&#8217;s identity applied to both <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv_x%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v_x}' title='{v_x}' class='latex' /> in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Omega}' title='{&#92;Omega}' class='latex' /> would give us an <em>integral representation formula</em> for harmonic functions</p>
<p>
<span id="more-615"></span></p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u%28x%29%3D%5Cint_%7B%5Cpartial+%5COmega%7D+u%28y%29%5Cfrac%7B%5Cpartial+v_x%28y%29%7D%7B%5Cpartial+%5Cnu%7DdS%28Y%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u(x)=&#92;int_{&#92;partial &#92;Omega} u(y)&#92;frac{&#92;partial v_x(y)}{&#92;partial &#92;nu}dS(Y)' title='&#92;displaystyle u(x)=&#92;int_{&#92;partial &#92;Omega} u(y)&#92;frac{&#92;partial v_x(y)}{&#92;partial &#92;nu}dS(Y)' class='latex' /></p>
<p>
This can actually be carried out rigorously for all reasonable domains <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Omega}' title='{&#92;Omega}' class='latex' />, but only in a few cases however, we know a useful expression for the functions <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cleft+%5C%7B+v_x%28y%29+%5Cright+%5C%7D_x%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;left &#92;{ v_x(y) &#92;right &#92;}_x}' title='{&#92;left &#92;{ v_x(y) &#92;right &#92;}_x}' class='latex' />. Happily for us, whenever <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Omega}' title='{&#92;Omega}' class='latex' /> is a ball there is a simple expression, and so, for any function <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> harmonic in a neighborhood of a ball <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_r%280%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_r(0)}' title='{B_r(0)}' class='latex' /> we have</p>
<blockquote><p><b>Theorem 1</b> <em></p>
<p>
Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> be a smooth harmonic function in some neighborhood of the ball <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_r%280%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_r(0)}' title='{B_r(0)}' class='latex' />, and let the dimension be <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bn%5Cgeq2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{n&#92;geq2}' title='{n&#92;geq2}' class='latex' />, then</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+u%28x%29%3D%5Cint_%7B%5Cpartial+B_r%7D%5Cfrac%7B1%7D%7Bn%5Calpha_n%7D+%5Cfrac%7Br%5E2-x%5E2%7D%7B%7Cx-y%7C%5En%7Du%28y%29dS%28y%29+%5C%3B%5C%3B%5C%3B%5C%3B+%5Cforall+x%5Cin+B_r%280%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle u(x)=&#92;int_{&#92;partial B_r}&#92;frac{1}{n&#92;alpha_n} &#92;frac{r^2-x^2}{|x-y|^n}u(y)dS(y) &#92;;&#92;;&#92;;&#92;; &#92;forall x&#92;in B_r(0)' title='&#92;displaystyle u(x)=&#92;int_{&#92;partial B_r}&#92;frac{1}{n&#92;alpha_n} &#92;frac{r^2-x^2}{|x-y|^n}u(y)dS(y) &#92;;&#92;;&#92;;&#92;; &#92;forall x&#92;in B_r(0)' class='latex' /></p>
<p>
</em></p></blockquote>
<p><p>
Here <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Calpha_n%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;alpha_n}' title='{&#92;alpha_n}' class='latex' /> is just the surface area of the <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bn-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{n-1}' title='{n-1}' class='latex' /> dimensional sphere, I will not derive it as this can be found in most introductory PDE textbooks (for instance, <a class="snap_noshots" href="http://books.google.com/books?id=jjnRA75GVB4C&amp;dq=Evans+partial+differential+equations&amp;printsec=frontcover&amp;source=bn&amp;hl=en&amp;ei=JTJRS-7uK9Sztge9yeG6CQ&amp;sa=X&amp;oi=book_result&amp;ct=result&amp;resnum=6&amp;ved=0CCMQ6AEwBQ#v=onepage&amp;q=&amp;f=false">Evan&#8217;s book</a>), suffice it to say that one needs to use the symmetries of Laplace&#8217;s equation (in particular under inversions) to manipulate the fundamental solution <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BV%28x%29%3D%7Cx%7C%5E%7B-n-2%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{V(x)=|x|^{-n-2}}' title='{V(x)=|x|^{-n-2}}' class='latex' /> (<img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bn+%5Cgeq+3%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{n &#92;geq 3}' title='{n &#92;geq 3}' class='latex' />) and build the function <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bv_x%28y%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{v_x(y)}' title='{v_x(y)}' class='latex' />.</p>
<p>
Note that this integral representation for <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> gives us as a corollary the mean value property (just take <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x}' title='{x}' class='latex' /> equal to the center of the ball, in this case <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{0}' title='{0}' class='latex' />), and it tells us that for other points <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx+%5Cin+B_r%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x &#92;in B_r}' title='{x &#92;in B_r}' class='latex' />, the value <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%28x%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u(x)}' title='{u(x)}' class='latex' /> is obtained via a weighted average of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> on the sphere, the average being balanced according to the position of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x}' title='{x}' class='latex' /> with respect to the sphere. By the way, this weight function</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+K%28x%2Cy%29%3D%5Cfrac%7B1%7D%7Bn%5Calpha_n%7D%5Cfrac%7Br%5E2-%7Cx%7C%5E2%7D%7B%7Cx-y%7C%5En%7D%2C+%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B+x+%5Cin+B_r%2C%5C%3B%5C%3B%5C%3B+y+%5Cin+%5Cpartial+B_r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle K(x,y)=&#92;frac{1}{n&#92;alpha_n}&#92;frac{r^2-|x|^2}{|x-y|^n}, &#92;;&#92;;&#92;;&#92;;&#92;; x &#92;in B_r,&#92;;&#92;;&#92;; y &#92;in &#92;partial B_r' title='&#92;displaystyle K(x,y)=&#92;frac{1}{n&#92;alpha_n}&#92;frac{r^2-|x|^2}{|x-y|^n}, &#92;;&#92;;&#92;;&#92;;&#92;; x &#92;in B_r,&#92;;&#92;;&#92;; y &#92;in &#92;partial B_r' class='latex' /></p>
<p>
is known as the Poisson kernel (for the ball). This representation formula also gives us directly another proof of Harnack&#8217;s inequality. It tells us even more, it says that if <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is continuous up to the boundary of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_r%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_r}' title='{B_r}' class='latex' />, then <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is Lipscthiz on the boundary, which can be seen by just looking at the term <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Br%5E2-%7Cx%7C%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{r^2-|x|^2}' title='{r^2-|x|^2}' class='latex' />. Finally, by differentiating the right hand side of the integral representation formula, we prove again the a priori estimate for the gradient I discussed last time:</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla+u%28x%29%3D%5Cfrac%7B1%7D%7Bn%5Calpha_n%7D%5Cint_%7B%5Cpartial+B_r%7D%5Cfrac%7B-2x%7Cx-y%7C%5E2-%28r%5E2-%7Cx%7C%5E2%29n%28x-y%29%7D%7B%7Cx-y%7C%5E%7Bn%2B2%7D%7Du%28y%29dy&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;nabla u(x)=&#92;frac{1}{n&#92;alpha_n}&#92;int_{&#92;partial B_r}&#92;frac{-2x|x-y|^2-(r^2-|x|^2)n(x-y)}{|x-y|^{n+2}}u(y)dy' title='&#92;displaystyle &#92;nabla u(x)=&#92;frac{1}{n&#92;alpha_n}&#92;int_{&#92;partial B_r}&#92;frac{-2x|x-y|^2-(r^2-|x|^2)n(x-y)}{|x-y|^{n+2}}u(y)dy' class='latex' /></p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cnabla+u%280%29%3D%5Cfrac%7B1%7D%7Bn%5Calpha_n%7D%5Cint_%7B%5Cpartial+B_r%7D%5Cfrac%7Bnr%5E2y%7D%7B%7Cy%7C%5E%7Bn%2B2%7D%7Du%28y%29dy%3D%5Cfrac%7B1%7D%7Br%7D%5Cfrac%7B1%7D%7B%5Calpha_nr%5E%7Bn-1%7D%7D%5Cint_%7B%5Cpartial+B_r%7D+y+u%28y%29dy&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;nabla u(0)=&#92;frac{1}{n&#92;alpha_n}&#92;int_{&#92;partial B_r}&#92;frac{nr^2y}{|y|^{n+2}}u(y)dy=&#92;frac{1}{r}&#92;frac{1}{&#92;alpha_nr^{n-1}}&#92;int_{&#92;partial B_r} y u(y)dy' title='&#92;displaystyle &#92;nabla u(0)=&#92;frac{1}{n&#92;alpha_n}&#92;int_{&#92;partial B_r}&#92;frac{nr^2y}{|y|^{n+2}}u(y)dy=&#92;frac{1}{r}&#92;frac{1}{&#92;alpha_nr^{n-1}}&#92;int_{&#92;partial B_r} y u(y)dy' class='latex' /></p>
<p>
taking absolute values we get <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%7C%5Cnabla+u%280%29%7C%5Cleq+%5Cfrac%7B1%7D%7Br%7D+%5Cfrac%7B1%7D%7B%5Calpha_n+r%5E%7Bn-1%7D%7D%5Cint_%7B%5Cpartial+B_r%7D%7Cu%28y%29%7Cdy%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{|&#92;nabla u(0)|&#92;leq &#92;frac{1}{r} &#92;frac{1}{&#92;alpha_n r^{n-1}}&#92;int_{&#92;partial B_r}|u(y)|dy}' title='{|&#92;nabla u(0)|&#92;leq &#92;frac{1}{r} &#92;frac{1}{&#92;alpha_n r^{n-1}}&#92;int_{&#92;partial B_r}|u(y)|dy}' class='latex' />, so the gradient is bounded by <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cfrac%7B1%7D%7Br%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;frac{1}{r}}' title='{&#92;frac{1}{r}}' class='latex' /> times the <em>average</em> of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> on the sphere of radius <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Br%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{r}' title='{r}' class='latex' />, which is actually a stronger estimate than what I proved last time, for the average is bounded by the supremum of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' />, thus</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%7C%5Cnabla+u%280%29%7C%5Cleq+%5Cfrac%7B1%7D%7Br%7D%5Csup+%5Climits_%7B%5Cpartial+B_r%7D+%7Cu%7C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle |&#92;nabla u(0)|&#92;leq &#92;frac{1}{r}&#92;sup &#92;limits_{&#92;partial B_r} |u|' title='&#92;displaystyle |&#92;nabla u(0)|&#92;leq &#92;frac{1}{r}&#92;sup &#92;limits_{&#92;partial B_r} |u|' class='latex' /></p>
<p>
(notice I had not specified the constant <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC_n%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C_n}' title='{C_n}' class='latex' /> last time I wrote this estimate, here we see that we may take <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC_n%3D1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C_n=1}' title='{C_n=1}' class='latex' />.)</p>
<p>
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			<wfw:commentRss>https://partialdifferentialequations.wordpress.com/2010/01/15/reviewing-the-regularity-theory-of-elliptics-pdes-via-the-laplace-equation-part-iii-representation-formulas/feed/</wfw:commentRss>
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			<media:title type="html">Nestor</media:title>
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		<title>Reviewing the regularity theory of elliptics PDEs via the Laplace equation. Part II.</title>
		<link>https://partialdifferentialequations.wordpress.com/2010/01/14/laplaceii/</link>
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		<pubDate>Thu, 14 Jan 2010 16:14:46 +0000</pubDate>
		<dc:creator>Nestor</dc:creator>
				<category><![CDATA[Partial Differential Equations]]></category>
		<category><![CDATA[A priori estimates]]></category>
		<category><![CDATA[harmonic functions]]></category>
		<category><![CDATA[Harnack's inequality]]></category>
		<category><![CDATA[Laplace equation]]></category>
		<category><![CDATA[mean value property]]></category>

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		<description><![CDATA[This is the second of a series of posts dealing with the regularity theory of elliptic equations. My motivation in writing these is outlined in the first post. Some consequences of Harnack&#8217;s inequality the Mean value property The mean value property is characteristic of harmonic functions, but the fact that harmonic functions control their pointwise [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=600&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>
This is the second of a series of posts dealing with the regularity theory of elliptic equations. My motivation in writing these is outlined in the <a class="snap_noshots" href="http://themathingpot.wordpress.com/2010/01/06/laplace/">first post</a>.</p>
<p>
<b>Some consequences of <s>Harnack&#8217;s inequality</s> the Mean value property</b></p>
<p>
The mean value property is characteristic of harmonic functions, but the fact that harmonic functions control their pointwise values by their local average is a general fact that is characteristic of elliptic equations (as we will see later, less sharp but more general theorems for nonlinear elliptic equations still have this flavor and are at the very heart of the regularity theory of fully nonlinear elliptic PDEs). Let me mention a few of its consequences, I already talked last time about Harnack&#8217;s inequality, as it follows from the mean value theorem, the mean value theorem (at least for harmonic functions) is more fundamental.</p>
<p>
<span id="more-600"></span></p>
<p>
First, and perhaps the most important consequence, is the pointwise <em>a priori</em> estimate for the derivatives of a harmonic function in terms of its supremum:</p>
<blockquote><p><b>Theorem 1 (A priori gradient estimate for harmonic functions)</b> <em></p>
<p>
Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> be a harmonic function in a ball <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_r%28y%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_r(y)}' title='{B_r(y)}' class='latex' />, then</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%7C%5Cnabla+u%28y%29%7C+%5Cleq+%5Cfrac%7BC_n%7D%7Br%7D+%5Csup+%5Climits_%7BB_r%28y%29%7Du%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle |&#92;nabla u(y)| &#92;leq &#92;frac{C_n}{r} &#92;sup &#92;limits_{B_r(y)}u(x)' title='&#92;displaystyle |&#92;nabla u(y)| &#92;leq &#92;frac{C_n}{r} &#92;sup &#92;limits_{B_r(y)}u(x)' class='latex' /></p>
<p>
</em></p></blockquote>
<p><p>
<em>Proof:</em>  Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> be a harmonic function in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_r%28y%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_r(y)}' title='{B_r(y)}' class='latex' />, by the mean value property, <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%28y%2Bh%29%3D+%28w_nr%5En%29%5E%7B-1%7D%5Cint_%7BB_%7Br%2F2%7D%28y%2Bh%29%7Du%28x%29dx%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u(y+h)= (w_nr^n)^{-1}&#92;int_{B_{r/2}(y+h)}u(x)dx}' title='{u(y+h)= (w_nr^n)^{-1}&#92;int_{B_{r/2}(y+h)}u(x)dx}' class='latex' /> as long as <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%7Ch%7C%3C%5Cfrac%7Br%7D%7B2%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{|h|&lt;&#92;frac{r}{2}}' title='{|h|&lt;&#92;frac{r}{2}}' class='latex' />, therefore</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%7Cu%28y%2Bh%29-u%28y%29%7C+%5Cleq+C_nr%5E%7B-n%7D+%5Cint_%7BB_%7Br%2F2%7D%28y%2Bh%29+%5CDelta+B_%7Br%2F2%7D%28y%29%7D%7Cu%28x%29%7Cdx&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle |u(y+h)-u(y)| &#92;leq C_nr^{-n} &#92;int_{B_{r/2}(y+h) &#92;Delta B_{r/2}(y)}|u(x)|dx' title='&#92;displaystyle |u(y+h)-u(y)| &#92;leq C_nr^{-n} &#92;int_{B_{r/2}(y+h) &#92;Delta B_{r/2}(y)}|u(x)|dx' class='latex' /></p>
<p>
(Recall <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BA+%5CDelta+B+%3D+A+%5Csetminus+B+%5Ccup+B+%5Csetminus+A%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{A &#92;Delta B = A &#92;setminus B &#92;cup B &#92;setminus A}' title='{A &#92;Delta B = A &#92;setminus B &#92;cup B &#92;setminus A}' class='latex' /> is called the symmetric difference of sets), now the set <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_%7Br%2F2%7D%28y%2Bh%29+%5CDelta+B_%7Br%2F2%7D%28y%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_{r/2}(y+h) &#92;Delta B_{r/2}(y)}' title='{B_{r/2}(y+h) &#92;Delta B_{r/2}(y)}' class='latex' /> lies in the union of two annuli with radii <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Br%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{r}' title='{r}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Br%2Bh%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{r+h}' title='{r+h}' class='latex' />, thus its volume is not larger than <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC_nr%5E%7Bn-1%7D%7Ch%7C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C_nr^{n-1}|h|}' title='{C_nr^{n-1}|h|}' class='latex' /> for a dimensional constant <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC_n%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C_n}' title='{C_n}' class='latex' />. We then have</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle++%5Cint_%7BB_%7Br%2F2%7D%28y%2Bh%29+%5CDelta+B_%7Br%2F2%7D%28y%29%7D%7Cu%28x%29%7Cdx+%5Cleq+C_nr%5E%7Bn-1%7D%7Ch%7C+%5Csup+%5Climits_%7BB_r%28y%29%7Du%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle  &#92;int_{B_{r/2}(y+h) &#92;Delta B_{r/2}(y)}|u(x)|dx &#92;leq C_nr^{n-1}|h| &#92;sup &#92;limits_{B_r(y)}u(x)' title='&#92;displaystyle  &#92;int_{B_{r/2}(y+h) &#92;Delta B_{r/2}(y)}|u(x)|dx &#92;leq C_nr^{n-1}|h| &#92;sup &#92;limits_{B_r(y)}u(x)' class='latex' /></p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%7Cu%28y%2Bh%29-u%28x%29%7C%5Cleq+%5Cfrac%7BC_n%7D%7Br%7D%7Ch%7C+%5Csup+%5Climits_%7BB_r%28y%29%7Du%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle |u(y+h)-u(x)|&#92;leq &#92;frac{C_n}{r}|h| &#92;sup &#92;limits_{B_r(y)}u(x)' title='&#92;displaystyle |u(y+h)-u(x)|&#92;leq &#92;frac{C_n}{r}|h| &#92;sup &#92;limits_{B_r(y)}u(x)' class='latex' /></p>
<p>
since the direction of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bh%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{h}' title='{h}' class='latex' /> is arbitrary and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^1}' title='{C^1}' class='latex' />, dividing both sides by <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%7Ch%7C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{|h|}' title='{|h|}' class='latex' /> and taking <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bh+%5Crightarrow+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{h &#92;rightarrow 0}' title='{h &#92;rightarrow 0}' class='latex' /> we obtain the a priori estimate. <img src='https://s-ssl.wordpress.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>
One may iterate this to estimate higher derivatives (thanks to the fact that the derivatives of a harmonic function are themselves harmonic). To obtain the estimate</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%7CD%5E%7B%28k%29%7Du%28y%29%7C+%5Cleq+%5Cfrac%7BC_%7Bn%2Ck%7D%7D%7Br%5Ek%7D+%5Csup+%5Climits_%7BB_r%28y%29%7Du%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle |D^{(k)}u(y)| &#92;leq &#92;frac{C_{n,k}}{r^k} &#92;sup &#92;limits_{B_r(y)}u(x)' title='&#92;displaystyle |D^{(k)}u(y)| &#92;leq &#92;frac{C_{n,k}}{r^k} &#92;sup &#92;limits_{B_r(y)}u(x)' class='latex' /></p>
<p>
I emphasize that these are <em>a priori</em> estimates, one needs to know <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> is already smooth to prove them, what they say is that the derivatives of all orders <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> are all controlled by the supremum of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' />!. In particular, a family of uniformly bounded harmonic functions is compact in every <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5Ek%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^k}' title='{C^k}' class='latex' />. Usually, the first time you learn about this phenomenon is when studying <a class="snap_noshots" href="http://en.wikipedia.org/wiki/Montel&#037;27s_theorem">Montel&#8217;s theorem</a> in a complex analysis.</p>
<p>
The a priori estimates and Harnack&#8217;s inequality also give a quick proof (which I will omit) of another classical result, but in potential theory, which I mentioned because it was due to Harnack himself:</p>
<blockquote><p><b>Theorem 2 (Harnack&#8217;s convergence theorem)</b> <em> Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_n%3A%5COmega+%5Crightarrow+%5Cmathbb%7BR%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_n:&#92;Omega &#92;rightarrow &#92;mathbb{R}}' title='{u_n:&#92;Omega &#92;rightarrow &#92;mathbb{R}}' class='latex' /> be a decreasing sequence of functions which are continuous in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cbar%7B%5COmega%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;bar{&#92;Omega}}' title='{&#92;bar{&#92;Omega}}' class='latex' /> and harmonic in the interior. Then they converge <b>uniformly</b> in compact sets of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Omega}' title='{&#92;Omega}' class='latex' /> to a smooth function <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%3A%5COmega+%5Crightarrow+%5Cmathbb%7BR%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u:&#92;Omega &#92;rightarrow &#92;mathbb{R}}' title='{u:&#92;Omega &#92;rightarrow &#92;mathbb{R}}' class='latex' /> which is harmonic. </em></p></blockquote>
<p>
<p>Since I just mentioned a priori estimates, I should recall the (one of many ) proofs of the fact that being harmonic even in some weak sense forces a function to be smooth and harmonic in the classical sense. Let&#8217;s say for instance, harmonic in the sense of distributions (we will revisit this theorem for other weak notions of harmonicity):</p>
<blockquote><p><b>Theorem 3 (Weak harmonic implies harmonic)</b> <em> Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> be a bounded measurable function in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Omega}' title='{&#92;Omega}' class='latex' /> such that</p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%5COmega+u%28x%29+%5CDelta+%5Cphi+%28x%29+dx+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_&#92;Omega u(x) &#92;Delta &#92;phi (x) dx = 0' title='&#92;displaystyle &#92;int_&#92;Omega u(x) &#92;Delta &#92;phi (x) dx = 0' class='latex' /></p>
<p>
for any smooth function <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cphi%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;phi}' title='{&#92;phi}' class='latex' /> with compact support in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Omega}' title='{&#92;Omega}' class='latex' />. Then <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> (after modifying it in at most a set of measure zero) is smooth in the interior of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Omega}' title='{&#92;Omega}' class='latex' /> and harmonic. </em></p></blockquote>
<p><p>
<em>Proof:</em>  Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cpsi_%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;psi_&#92;epsilon}' title='{&#92;psi_&#92;epsilon}' class='latex' /> be an approximation to the identity given by a <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E%5Cinfty_c%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^&#92;infty_c}' title='{C^&#92;infty_c}' class='latex' /> kernel <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cpsi_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;psi_1}' title='{&#92;psi_1}' class='latex' /> which is radially symmetric and supported in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%280%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1(0)}' title='{B_1(0)}' class='latex' />. Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_%5Cepsilon+%3D+u+%5Cstar+%5Cpsi_%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_&#92;epsilon = u &#92;star &#92;psi_&#92;epsilon}' title='{u_&#92;epsilon = u &#92;star &#92;psi_&#92;epsilon}' class='latex' />, then for each <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cepsilon%3E0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;epsilon&gt;0}' title='{&#92;epsilon&gt;0}' class='latex' /> and any compact <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BK+%5Csubset+%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{K &#92;subset &#92;Omega}' title='{K &#92;subset &#92;Omega}' class='latex' /> the functions <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_&#92;epsilon}' title='{u_&#92;epsilon}' class='latex' /> (<img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;epsilon}' title='{&#92;epsilon}' class='latex' /> small enough depending on the distance between <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BK%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{K}' title='{K}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cpartial+%5COmega%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;partial &#92;Omega}' title='{&#92;partial &#92;Omega}' class='latex' />) are smooth with bounded derivatives of any orders, moreover, they are all uniformly bounded in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BL%5E%5Cinfty%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{L^&#92;infty}' title='{L^&#92;infty}' class='latex' /> by the boundedness assumption on <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' />. Now, using the symmetry of the kernel and Fubini&#8217;s theorem, one can see that for any <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cphi+%5Cin+C%5E%5Cinfty_c%28%5COmega%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;phi &#92;in C^&#92;infty_c(&#92;Omega)}' title='{&#92;phi &#92;in C^&#92;infty_c(&#92;Omega)}' class='latex' /></p>
<p><p align="center"><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint_%5COmega+u_%5Cepsilon%28x%29+%5CDelta+%5Cphi+%28x%29+dx+%3D+%5Cint_%5COmega+u%28x%29+%5CDelta+%5Cphi_%5Cepsilon%28x%29dx%3D0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;int_&#92;Omega u_&#92;epsilon(x) &#92;Delta &#92;phi (x) dx = &#92;int_&#92;Omega u(x) &#92;Delta &#92;phi_&#92;epsilon(x)dx=0' title='&#92;displaystyle &#92;int_&#92;Omega u_&#92;epsilon(x) &#92;Delta &#92;phi (x) dx = &#92;int_&#92;Omega u(x) &#92;Delta &#92;phi_&#92;epsilon(x)dx=0' class='latex' /></p>
<p> and since each <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_&#92;epsilon}' title='{u_&#92;epsilon}' class='latex' /> is smooth we have <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5CDelta+u_%5Cepsilon+%3D+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Delta u_&#92;epsilon = 0}' title='{&#92;Delta u_&#92;epsilon = 0}' class='latex' />. Furthermore, by the a priori estimates the functions <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_&#92;epsilon}' title='{u_&#92;epsilon}' class='latex' /> are also uniformly bounded <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5Ek%28K%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^k(K)}' title='{C^k(K)}' class='latex' />, for any <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bk+%5Cgeq+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{k &#92;geq 0}' title='{k &#92;geq 0}' class='latex' />. Then we know (by Arzela-Ascoli) that a suitable subsequence of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu_%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u_&#92;epsilon}' title='{u_&#92;epsilon}' class='latex' /> with <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cepsilon%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;epsilon}' title='{&#92;epsilon}' class='latex' /> converges uniformly in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BK%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{K}' title='{K}' class='latex' /> to a function which lies in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5Ek%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^k}' title='{C^k}' class='latex' /> (for <em>any</em> <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bk%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{k}' title='{k}' class='latex' />), since they also must converge to <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%28x%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u(x)}' title='{u(x)}' class='latex' /> a.e.(by Lebesgue&#8217;s differentiation theorem) we conclude that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> agrees a.e. with a smooth harmonic function, as we wanted to prove.</p>
<p>
<img src='https://s-ssl.wordpress.com/latex.php?latex=%5CBox&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Box' title='&#92;Box' class='latex' /></p>
<p>
I think that I will stop here for now. Tomorrow: I will review the Poisson kernel to give the potential theoretic proof of the Mean value property, Harnack&#8217;s inequality and the (a priori) gradient estimates for harmonic functions, and after that, it will be the Calder&oacute;n-Zygmund estimates.</p>
<p>
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		<title>Joint Mathematics Meetings in San Francisco -Blog!</title>
		<link>https://partialdifferentialequations.wordpress.com/2010/01/13/joint-mathematics-meetings-in-san-francisco-blog/</link>
		<comments>https://partialdifferentialequations.wordpress.com/2010/01/13/joint-mathematics-meetings-in-san-francisco-blog/#comments</comments>
		<pubDate>Thu, 14 Jan 2010 02:47:30 +0000</pubDate>
		<dc:creator>Nestor</dc:creator>
				<category><![CDATA[quick posts]]></category>
		<category><![CDATA[Adriana Salerno]]></category>
		<category><![CDATA[AMS]]></category>
		<category><![CDATA[Conference]]></category>
		<category><![CDATA[Joint Math Meetings]]></category>

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		<description><![CDATA[&#8230;and now for a little advertisement: My friend and former UT graduate student Adriana Salerno (currently at Bates) will be running the 2010 AMS Joint Math meetings blog. She was also in charge of the blog in previous years (you can check them out here and here). I recommend you check it out in the [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=596&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>&#8230;and now for a little advertisement:</p>
<p>My friend and former UT graduate student <a href="http://www.ma.utexas.edu/users/asalerno/">Adriana Salerno </a>(currently at <a href="http://www.bates.edu">Bates</a>) will be running the <a href="http://www.ams.org/blog/jmm2010/">2010 AMS Joint Math meetings blog</a>. She was also in charge of the blog in previous years (you can check them out <a href="http://www.ams.org/blog/jmm2008/?page_id=12">here</a> and <a href="http://www.ams.org/blog/jmm2009/">here</a>). I recommend you check it out in the next few days to see what has been going on at the meetings (specially if, just like me, you don&#8217;t happen to be in San Francisco this week).</p>
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		<title>Reviewing the regularity theory of elliptics PDEs via the Laplace equation. Part I.</title>
		<link>https://partialdifferentialequations.wordpress.com/2010/01/06/laplace/</link>
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		<pubDate>Wed, 06 Jan 2010 20:03:13 +0000</pubDate>
		<dc:creator>Nestor</dc:creator>
				<category><![CDATA[Partial Differential Equations]]></category>
		<category><![CDATA[harmonic functions]]></category>
		<category><![CDATA[Harnack's inequality]]></category>
		<category><![CDATA[Laplace equation]]></category>
		<category><![CDATA[mean value property]]></category>

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		<description><![CDATA[There is a tedious, simple but hopefully fruitful exercise I always wanted to do. It is to review all the different proofs of the Harnack inequality and regularity of solutions to elliptic equations that I know, but only for the Laplace equation. First, because it is a good way to really get your hands on [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=566&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>There is a tedious, simple but hopefully fruitful exercise I always wanted to do. It is to review all the different proofs of the Harnack inequality and regularity of solutions to elliptic equations that I know, <em>but only </em> for the <a class="snap_noshots" href="http://www.en.wikipedia.org/wiki/Laplace_equation">Laplace equation</a>. First, because it is a good way to really get your hands on some of the ideas of several deep theorems (like those of De Giorgi-Nash-Moser and Krylov-Safonov) in the simplest possible setting. Second, because looking at all the different proofs it is possible to trace the evolution of analysis and PDEs through the last century (and a bit before that) and appreciate the level maturity reached in several fields: potential theory, singular integrals, calculus of variations, fully non linear elliptic PDE and free boundary problems. The `simple&#8217; and `elementary&#8217; Laplace equation lies at the intersection of all these fields, so every new breakthrough reflected on our understanding of this equation, each new proof emphasizing a different approach or point of view. Each of the proofs that I will discuss are based on one of the following:</p>
<ul>
<li> The mean value property (the proof you learn in your typical complex variables or introductory PDE course).</li>
<li> The Poisson Kernel for the ball (the proof from potential theory).</li>
<li> The Calderón-Zygmund theorem (ok not exactly a `Harnack inequality&#8217;, but it should be on this list anyway) which uses the machinery of singular integrals.</li>
<li> The De Giorgi-Nash-Moser theorem, which follows the variational point of view and it is best suited for quasilinear equations or equations in divergence form.</li>
<li> The Aleksandrov-Bakelman-Pucci estimate and the Krylov-Safonov&#8217;s `Harnack&#8217;s inequality&#8217;, which follows the comparison principle point of view and it is best suited for fully non linear equations or equations in non-divergence form.</li>
</ul>
<p>So I am going to review each theorem and its proof but only for Laplace&#8217;s equation: <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5CDelta+u+%3D+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Delta u = 0}' title='{&#92;Delta u = 0}' class='latex' />. To start off easy, I am going to do first the proof via the mean value property.</p>
<p><strong> First proof: mean value property </strong></p>
<p>The mean value property says basically this</p>
<p><em>Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> be a <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BC%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{C^2}' title='{C^2}' class='latex' /> function in the unit ball <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1}' title='{B_1}' class='latex' /> of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cmathbb%7BR%7D%5En%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;mathbb{R}^n}' title='{&#92;mathbb{R}^n}' class='latex' />. If <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5CDelta+u+%3D+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Delta u = 0}' title='{&#92;Delta u = 0}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BS%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{S}' title='{S}' class='latex' /> is a sphere contained in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1}' title='{B_1}' class='latex' /> and centered at <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx_0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x_0}' title='{x_0}' class='latex' />, then <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%28x_0%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u(x_0)}' title='{u(x_0)}' class='latex' /> equals the average of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> on <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BS%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{S}' title='{S}' class='latex' /> </em></p>
<p>It is not hard to prove with some calculus, one basically looks at the function `Average of <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> on the sphere of radius <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Br%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{r}' title='{r}' class='latex' /> centered at <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx_0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x_0}' title='{x_0}' class='latex' />&#8216;=<img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%28r%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(r)}' title='{f(r)}' class='latex' /> and shows that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%27%28r%29%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f&#039;(r)=0}' title='{f&#039;(r)=0}' class='latex' />, and since by continuity <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%280%29%3Du%28x_0%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f(0)=u(x_0)}' title='{f(0)=u(x_0)}' class='latex' />, the theorem follows. To show <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bf%27%28r%29%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{f&#039;(r)=0}' title='{f&#039;(r)=0}' class='latex' /> one sees (by say, a change of variables) that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5Cfrac%7Bd%7D%7Bdr%7D+%5Cfrac%7B1%7D%7B%7CS%7C%7D%5Cint_%7BS_r%7Du%28x%29d%5Csigma+%3D%5Cfrac%7B1%7D%7B%7CS%7D%5Cint_%7BS_r%7Du_nd%5Csigma%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;frac{d}{dr} &#92;frac{1}{|S|}&#92;int_{S_r}u(x)d&#92;sigma =&#92;frac{1}{|S}&#92;int_{S_r}u_nd&#92;sigma}' title='{&#92;frac{d}{dr} &#92;frac{1}{|S|}&#92;int_{S_r}u(x)d&#92;sigma =&#92;frac{1}{|S}&#92;int_{S_r}u_nd&#92;sigma}' class='latex' /> and this last integral is zero thanks to Stokes&#8217; theorem and the fact that <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B%5CDelta+u+%3D+0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{&#92;Delta u = 0}' title='{&#92;Delta u = 0}' class='latex' />. Moreove, integrating the result with respect to the radius of the sphere one gets the same statement where instead of average over a <em>sphere</em> we have an average over a <em>ball</em>.</p>
<p>With this, one may prove easily Harnack&#8217;s inequality for harmonic functions, which I will state formally for the first time</p>
<blockquote><p><strong>Theorem 1</strong> <em> For any nonnegative harmonic function <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bu%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{u}' title='{u}' class='latex' /> in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1}' title='{B_1}' class='latex' /> we have the inequality<br />
</em></p>
<p><em><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cdisplaystyle++u%28x%29+%5Cleq+2%5Enu%280%29+%5C%3B%5C%3B%5C%3B+%5Cmbox%7B+for+all+%7D+x+%5Cin+B_%7B1%2F2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle  u(x) &#92;leq 2^nu(0) &#92;;&#92;;&#92;; &#92;mbox{ for all } x &#92;in B_{1/2}' title='&#92;displaystyle  u(x) &#92;leq 2^nu(0) &#92;;&#92;;&#92;; &#92;mbox{ for all } x &#92;in B_{1/2}' class='latex' /></em></p>
<p><em> </em></p></blockquote>
<p><em>Proof</em>. Let <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx+%5Cin+B_%7B1%2F2%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x &#92;in B_{1/2}}' title='{x &#92;in B_{1/2}}' class='latex' />, then the ball of radius <img src='https://s-ssl.wordpress.com/latex.php?latex=%7B1%2F2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{1/2}' title='{1/2}' class='latex' /> centered at <img src='https://s-ssl.wordpress.com/latex.php?latex=%7Bx%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{x}' title='{x}' class='latex' /> (call it <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B}' title='{B}' class='latex' />) is completely contained in <img src='https://s-ssl.wordpress.com/latex.php?latex=%7BB_1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='{B_1}' title='{B_1}' class='latex' />, thus by the mean value property</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=u%28x%29%3D%5Cint_B+u%28y%29dy+&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='u(x)=&#92;int_B u(y)dy ' title='u(x)=&#92;int_B u(y)dy ' class='latex' /></p>
<p>but again since <img src='https://s-ssl.wordpress.com/latex.php?latex=B&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='B' title='B' class='latex' /> is contained in <img src='https://s-ssl.wordpress.com/latex.php?latex=B_%7B1%7D&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='B_{1}' title='B_{1}' class='latex' /> and <img src='https://s-ssl.wordpress.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='u' title='u' class='latex' /> is nonnegative we have <img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cfrac%7B1%7D%7B%7CB%7C%7D%5Cint_B+u%28y%29dy+%5Cleq+%5Cfrac%7B2%5En%7D%7B%7CB_1%7C%7D+%5Cint_%7BB_1%7Du%28y%29dy%5Cleq2%5Enu%280%29&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;frac{1}{|B|}&#92;int_B u(y)dy &#92;leq &#92;frac{2^n}{|B_1|} &#92;int_{B_1}u(y)dy&#92;leq2^nu(0)' title='&#92;frac{1}{|B|}&#92;int_B u(y)dy &#92;leq &#92;frac{2^n}{|B_1|} &#92;int_{B_1}u(y)dy&#92;leq2^nu(0)' class='latex' />, again by the mean value property. This finishes the proof.</p>
<p>That is for today, in the next post I will explain some of the consequences of this theorem and maybe move on to the proof with potential theory methods.</p>
<p>(Note: this post was made using Luca Trevisan&#8217;s <a class="snap_noshots" href="http://lucatrevisan.wordpress.com/latex-to-wordpress/">Latex to WordPress</a> program, which is very useful although I am still getting used to using it. It allows you to prepare your post in a latex editor and then translate it into HTML code which WordPress can read, I strongly recommend it)</p>
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		<title>New year, new posts</title>
		<link>https://partialdifferentialequations.wordpress.com/2010/01/04/new-year-new-posts/</link>
		<comments>https://partialdifferentialequations.wordpress.com/2010/01/04/new-year-new-posts/#comments</comments>
		<pubDate>Mon, 04 Jan 2010 22:22:54 +0000</pubDate>
		<dc:creator>Nestor</dc:creator>
				<category><![CDATA[quick posts]]></category>

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		<description><![CDATA[After 4 months of inactivity, I am taking up again the task of updating the blog, which has suffered of neglect due to my terrible time management skills. I am not going to take off from where I left last time (namely, the posts about the Minkowski problem, which I will finish, someday), but instead [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=563&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>After 4 months of inactivity, I am taking up again the task of updating the blog, which has suffered of neglect due to my terrible time management skills.</p>
<p>I am not going to take off from where I left last time (namely, the posts about the Minkowski problem, which I will finish, someday), but instead will start the year with some shorter, lighter posts. I plant to start with a few posts about varifolds vs currents vs BV sets, and also about the <a href="http://en.wikipedia.org/wiki/Harnack_inequality">Harnack inequality</a>, <em>maybe </em>later I will write a bit about topics from phase transitions such as the <a href="http://en.wikipedia.org/wiki/Stefan_problem">Stefan problem</a> or the <a href="http://en.wikipedia.org/wiki/Cahn%E2%80%93Hilliard_equation">Cahn-Hilliard equation</a></p>
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		<title>If you want to kill your productivity, move to a new house!</title>
		<link>https://partialdifferentialequations.wordpress.com/2009/08/03/if-you-want-to-kill-your-productivity-move-to-a-new-house/</link>
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		<pubDate>Mon, 03 Aug 2009 18:28:18 +0000</pubDate>
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				<category><![CDATA[Differential geometry]]></category>
		<category><![CDATA[quick posts]]></category>

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		<description><![CDATA[I know things have been extremely slow lately, but I was moving last week (and well, that means packing everything, moving things to the new house, cleaning the old house, unpacking things at the new one&#8230; well, you get the picture). My goal for this week is presenting Aleksandrov&#8217;s solution to  the Minkowski problem (see [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=partialdifferentialequations.wordpress.com&amp;blog=15644183&amp;post=550&amp;subd=partialdifferentialequations&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>I know things have been extremely slow lately, but I was moving last week (and well, that means packing everything, moving things to the new house, cleaning the old house, unpacking things at the new one&#8230; well, you get the picture).</p>
<p>My goal for this week is presenting Aleksandrov&#8217;s solution to  the Minkowski problem (see an earlier <a href="http://themathingpot.wordpress.com/2009/06/04/the-minkowski-problem-and-the-monge-ampere-equation/">post</a> I did introducing this problem). So I am going to leave you a problem as a preview, it is a sort of discrete version of the Minkowski problem:</p>
<p>Let <img src='https://s-ssl.wordpress.com/latex.php?latex=n_1%2C...%2Cn_k&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='n_1,...,n_k' title='n_1,...,n_k' class='latex' />  be a family of non-coplanar unit vectors in <img src='https://s-ssl.wordpress.com/latex.php?latex=%5Cmathbb%7BR%7D%5E3&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;mathbb{R}^3' title='&#92;mathbb{R}^3' class='latex' /> and let <img src='https://s-ssl.wordpress.com/latex.php?latex=%5Calpha_1%2C...%2C%5Calpha_k&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;alpha_1,...,&#92;alpha_k' title='&#92;alpha_1,...,&#92;alpha_k' class='latex' /> be positive numbers such that</p>
<p><img src='https://s-ssl.wordpress.com/latex.php?latex=%5Csum+%5Climits_%7Bi%3D1%7D%5Ek+%5Calpha_in_i%3D0&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;sum &#92;limits_{i=1}^k &#92;alpha_in_i=0' title='&#92;sum &#92;limits_{i=1}^k &#92;alpha_in_i=0' class='latex' /></p>
<p>Then, show that there exists a convex closed polyhedron with exactly <img src='https://s-ssl.wordpress.com/latex.php?latex=k&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='k' title='k' class='latex' /> faces with normal vectors given by <img src='https://s-ssl.wordpress.com/latex.php?latex=n_1%2C...%2Cn_k&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='n_1,...,n_k' title='n_1,...,n_k' class='latex' /> and corresponding areas <img src='https://s-ssl.wordpress.com/latex.php?latex=%5Calpha_1%2C...%2C%5Calpha_k&amp;bg=ffffff&amp;fg=545454&amp;s=0' alt='&#92;alpha_1,...,&#92;alpha_k' title='&#92;alpha_1,...,&#92;alpha_k' class='latex' />. Plus, this polyhedron is unique up to translation.</p>
<p>This is fact is not surprising (since it is not hard to check that any polyhedron has this property), but the proof is far from trivial. As you may guess, the proof cannot be constructive, it will use a continuity argument to show that there must be at least one such polyhedron. I will present this in my next post.</p>
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